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andreev551 [17]
3 years ago
15

4. An airplane maintains a constant acceleration of 4.0 m/s2 [E] as it speeds up from 16 m/s [E] to 28 m/s [E].

Physics
1 answer:
ki77a [65]3 years ago
6 0

Answer:

gyvtu jyut

Explanation:

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Find your acceleration from 8.3 m/s to 12.5 m/s in 1.24 seconds.
balu736 [363]

The <u>average</u> acceleration for an object undergoing this change in velocity is

(12.5 m/s - 8.3 m/s) / (1.24 s) = (4.2 m/s) / (1.24 s) ≈ 3.4 m/s²

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2 years ago
First law of equilibrium
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Answer:

For an object to be an equilibrium it must be experiencing no acceleration.

Explanation:

Hope it helps.

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Which of the following statements is true about light? A. Light needs a medium through which to travel B. Light can not be diffr
maksim [4K]
From that ragged, motley list of statements, only 'C' is true.
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3 years ago
Lasers emit light of a certain frequency in one, precise direction. The light that a laser emits can be tuned to have a high fre
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Answer:

An ultra intense laser is one with which intensities greater than 1015 W cm-2 can be achieved.

Explanation:

This intensity, which was the upper limit of lasers until the invention of the Chirped Pulse Amplification, CPA technique, is the value around which nonlinear effects on the transport of radiation in materials begin to appear.

Currently, the most powerful lasers reach intensities of the order of 1021W cm-2 and powers of Petawatts, PW, in each pulse. This range of intensities has opened the door for lasers to a multitude of disciplines and scientific areas traditionally reserved for accelerators and nuclear reactors, applying as generators of high-energy electron, ion, neutron and photon beams, without the need for expensive infrastructure.

8 0
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A 1.2 L weather balloon on the ground has a temperature of 25°C and is at atmospheric pressure (1.0 atm). When it rises to an el
Irina-Kira [14]

Answer:

71.19 C

Explanation:

25C = 25 + 273 = 298 K

Applying the ideal gas equation we have

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}

where P, V and T are the pressure, volume and temperature of the gas at 1st and 2nd stage, respectively. We can solve for the temperature and the 2nd stage:

T_2 = T_1\frac{P_2V_2}{P_1V_1} = 298\frac{0.77*1.8}{1.2*1} = 298*1.155 = 344.19 K = 344.19 - 273 = 71.19 C

4 0
3 years ago
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