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emmasim [6.3K]
2 years ago
13

A family consumes 2.5 gallons of milk per week. How many liters of milk do they need to buy for one month? (Assume there are exa

ctly 4 weeks in 1 month) SHOW WORK
Chemistry
1 answer:
Arlecino [84]2 years ago
3 0

Answer:

37.85 liters

Explanation:

they need 10 gallons for a month (2.5*4)

after that, convert gallons to liters (conversion to liters= 3.785)

10*3.7585= 37.85

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For this, we first calculate molecular weight of MgSiO₃:
Atomic masses:
Mg = 24
Si = 28
O = 16

Mr = 24 + 28 + 16 x 3
Mr = 100

moles = mass / Mr
moles = 237 / 100
moles = 2.37
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What do atoms form when they bond chemically?
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Why did Rutherford choose alpha particles in his experiment?
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3 years ago
What is the molarity of a solution in which 7.1 g of sodium sulfate is dissolved in enough water to make 100. mL of solution?
Sidana [21]

Answer:

0.50 M

Explanation:

Given data

  • Mass of sodium sulfate (solute): 7.1 g
  • Volume of solution: 100 mL

Step 1: Calculate the moles of the solute

The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

7.1g \times \frac{1mol}{142.02g} = 0.050mol

Step 2: Convert the volume of solution to liters

We will use the relation 1 L = 1000 mL.

100mL \times \frac{1L}{1000mL} =0.100L

Step 3: Calculate the molarity of the solution

M = \frac{moles\ of\ solute }{liters\ of\ solution} = \frac{0.050mol}{0.100L} =0.50 M

3 0
3 years ago
Read 2 more answers
If 50.0 g of water saturated with potassium chloride at 80.0°C is slowly evaporator to dryness, how many grams of the dry salt w
balu736 [363]

Answer:

25.0 g.

Explanation:

  • From the solubility curve that is shown in the attached image, the solubility of KCl per 100.0 g of water is about 50.0 g.
  • <em>So, a saturated solution of KCl in 50.0 g of water will contain about 25.0 g.</em>
  • <em>Thus, the grams of the dry salt that will be recovered is 25.0 g.</em>

5 0
3 years ago
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