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muminat
3 years ago
6

A student wants to determine the coefficient of static friction μ between a block of wood and an adjustable inclined plane. Of t

he following, the minimum additional equipment the student needs to determine a value for μ is
Physics
1 answer:
Cloud [144]3 years ago
7 0

Answer:

A protractor to measure the angle of the inclined plane with the horizontal

Explanation:

The student needs to lift the free end of the adjustable inclined plane until the object barely starts sliding, and measure the angle at which such happens. At that point, the force of friction equals the component of the weight in the direction of the incline. That is:

f=\mu\,* N = \mu * m g\, cos(\theta)

and  w_{//}= m\,g\,sin(\theta)

Then  

f = w_{//}\\\mu *\,m \,g\,cos(\theta) = m\,g\,sin(\theta)\\\mu = tan(\theta)

and therefore, the coefficient of static friction is fully determined just by calculating the tangent of the angle that the incline forms with the horizontal.

Then the only extra instrument needed is a protractor to measure the angle.

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Maslowich
When I went through with the math, the answer I came upon was: 
<span>6.67 X 10^14 </span>

<span>Here is how I did it: First of all we need to know the equation. </span>

<span>c=nu X lamda </span>
<span>(speed of light) = (frequency)(wavelength) </span>
<span>(3.0 X 10^8 m/s) = (frequency)(450nm) </span>

<span>We want the answer in meters so we need to convert 450nm to meters. </span>
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Given the vector A with components Ax = 2.00, Ay = 6.00, the vector B with components Bx = 2.00, By = 22.00, and the vector D =
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Answer:

<em>The magnitude of vector d is 16 and the angle with the x-axis is 270°</em>

Explanation:

<u>Operations With Vectors</u>

Given two vectors in rectangular components:

\vec a=(ax,ay)\ ,\  \vec b=(bx,by)

The sum of the vectors is:

\vec a+\vec b=(ax+bx,ay+by)

The difference between the vectors is:

\vec a-\vec b=(ax-bx,ay-by)

The magnitude of \vec a is:

|\vec a|=\sqrt{ax^2+ay^2}

The angle \vec a makes with the horizontal positive direction is:

\displaystyle \tan\theta=\frac{ay}{ax}\\

The question provides the vectors:

\vec a=(2,6)

\vec b=(2,22)

\vec d=\vec a-\vec b

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\vec d=(2,6)-(2,22)=(0,-16)

The magnitude of \vec d is:

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The magnitude of vector d is 16 and the angle with the x-axis is 270°

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