Answer:
a) E = 1.47 × 10^5 N/C
b) south
Explanation:
The magnitude of an electric field can be defined mathematically as;
E = F/q ........1
Where,
E = magnitude of the electric field
F = electric force
q = charge on the proton
Given;
F = 2.36 × 10^-14 N
Note that charge on a proton is known as Qp = 1.602 × 10^-19 C
q = 1.602 × 10^-19 C
Substituting into equation 1, we have;
E = 2.36 × 10^-14 N/1.602 × 10^-19 C
E = 1.47 × 10^5 N/C
b) The direction of the electric field;
From equation 1
E = F/q ........1
since both electric field and electric force are vector quantity and q is a positive charge (constant), then both the electric field and electric force would be parallel to each other. Therefore the electric field is directed to the south also.
(When a vector is multiplied by a positive constant the direction remains the same)
Answer:
0.0815
Explanation:
Mechanical advantage is output force/input force. So all you have to do is 55.0N/675N ~ 0.0815
Hope this helped!
Answer: The most likely identity of the substance is iron.
Explanation:
The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q = Heat absorbed=
Joules
m= mass of substance = 11.9 g
c = specific heat capacity = ?
Initial temperature of the water =
= 25.0°C
Final temperature of the water =
= 45.0°CChange in temperature ,
Putting in the values, we get:


The specific heat of 0.45 is for iron and thus the substance is iron.
A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
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Answer:
v = 12.12 m/s
Explanation:
Given that,
The mass of the cart, m = 75 kg
The roller coaster begins 15 m above the ground.
We need to find the velocity of the cart halfway to the ground. Let the velocity be v. Using the conservation of energy at this position, h = 15/2 = 7.5 m

So, the velocity of the cart is 12.12 m/s.