Ask question

Ask question

All categories

3 years ago

11

Use this scenario to answer the four following questions. A person is on a sled on top of a snow covered hill. The vertical dist

ance from the top of the hill to the bottom is 12 meters. The sled and the person riding it have a combined mass of 60 kg. To start, person is pushed. The initial velocity is 1 m/s. At the bottom of the hill, the sled and the person have a velocity of 10 m/s. Use g=9.8 m/s2 or g=10 m/s2 for the gravitational acceleration. What is the initial total mechanical energy of the person and their sled?

1 answer:

jekas [21]3 years ago

7 0

Answer:7086 J

Explanation:

Given

height of hill from ground(h)=12 m

combined mass of sled and man(m)=60 kg

initial velocity(u)=1 m/s

at bottom velocity(v)=10 m/s

Total mechanical energy of the person

E=Potential Energy+Kinetic Energy

$E=mgh+\frac{mv^2}{2}$

$E=60\times 9.8\times 12+\frac{60\times 1^2}{2}$

E=7056+30=7086 J

You might be interested in

An expensive vacuum system can achieve a pressure as low as 1.00×10^{-7} N/m^2 at 20ºC . How many atoms are there in a cubic cen

marta [7]

Answer:

$24.70818432141\times 10^7\ atoms$

Explanation:

P = Pressure = $1\times 10^{-7}\ N/m^2$

V = Volume = 1 cm³

n = Amount of substance

N = Number of atoms

$N_A$ = Avogadro's constant = $6.022\times 10^{23}\ /mol$

R = Gas constant = 8.314 J/k mol

T = Temperature = 273.15+20 = 293.15 K

From the ideal gas law

$PV=nRT\\\Rightarrow n=\frac{PV}{RT}$

$n=\frac{N}{N_A}$

$\frac{N}{N_A}=\frac{PV}{RT}\\\Rightarrow N=N_A\times \frac{PV}{RT}\\\Rightarrow N=\frac{1\times 10^{-7}\times 1\times 10^{-6}}{8.314\times 293.15}\times 6.022\times 10^{23}\\\Rightarrow N=24708184.32141\ atoms=24.70818432141\times 10^7\ atoms$

The number of atoms is $24.70818432141\times 10^7\ atoms$

8 0

3 years ago

A marble slides without friction in a vertical loop around the inside of a smooth, 28.6 cm diameter horizontal pipe. The marble'

Leviafan [203]

Answer:3.49 m/s

Explanation:

Given

Speed of marble at Bottom $v=4.22 m/s$

Diameter of loop $d=28.6 cm$

As Energy is conserved therefore Energy at top is equal to energy at bottom

$E_T=E_B$

$\frac{mv^2}{2}+mgh=\frac{mv_0^2}{2}$ ,where $v_0$ is the velocity at bottom

$\frac{v^2}{2}+gh=\frac{v_0^2}{2}$

$v_0^2=v^2+2gh$

$v^2=v_0^2-2gh$

$v=\sqrt{v_0^2-2gh}$

$v=\sqrt{4.22^2-2\times 9.8\times 0.286}$

$v=\sqrt{17.8084-5.6056}$

$v=3.49 m/s$

7 0

3 years ago

Best Answer will receive BRAINLIEST One consequence of Newton's third law of motion is that __________. A. every object that has

In-s [12.5K]

One consequence of Newton's third law of motion is that all actions have equal and opposite reactions. <em>(C)</em>

In fact, that's pretty much what the law itself says in so many words.

7 0

3 years ago

Read 2 more answers

What are the first three harmonics of a note produced on a 0.31 m long violin string if the waves on this string have a speed of

bezimeni [28]

Is that what you are looking for?

4 0

2 years ago

3. According to the article, why did Europeans so quickly accept that the sun did move and change?

Sphinxa [80]

Answer:A

Explanation:because it is good

5 0

3 years ago

Read 2 more answers