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vlada-n [284]
3 years ago
11

Use this scenario to answer the four following questions. A person is on a sled on top of a snow covered hill. The vertical dist

ance from the top of the hill to the bottom is 12 meters. The sled and the person riding it have a combined mass of 60 kg. To start, person is pushed. The initial velocity is 1 m/s. At the bottom of the hill, the sled and the person have a velocity of 10 m/s. Use g=9.8 m/s2 or g=10 m/s2 for the gravitational acceleration. What is the initial total mechanical energy of the person and their sled?
Physics
1 answer:
jekas [21]3 years ago
7 0

Answer:7086 J

Explanation:

Given

height of hill from ground(h)=12 m

combined mass of sled and man(m)=60 kg

initial velocity(u)=1 m/s

at bottom velocity(v)=10 m/s

Total mechanical energy of the person

E=Potential Energy+Kinetic Energy

E=mgh+\frac{mv^2}{2}

E=60\times 9.8\times 12+\frac{60\times 1^2}{2}

E=7056+30=7086 J

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Naya [18.7K]

Answer:

A turbine spins the water to generate electricity.

Explanation:

This is impoundment facility is called a hydro electric power dam, it is basically a big hydropower system which uses the dam to store river water in a reservoir. The water released from the reservoir flows directly through a turbine, the turbine spins it, which afterwards activates a generator to generate electricity.

6 0
3 years ago
For a particular scientific experiment, it is important to be completely isolated from any magnetic field, including the earth's
Alexus [3.1K]

Answer:

50000 μT

Explanation:

From the given information:

the diameter of the loop = 1.0 mm = 0.001 m

no of turns (N) = 200

current (I) = 0.199 A

radius = d/2 = 0.001/2

= 5 × 10⁻⁴ m

Recall that;

the magnetic field at the centre of circular wire is:

= \dfrac{\mu I N}{2R}

= \dfrac{4 \pi \times 10^{-7} \times 200 \times0.199}{2\times 5\times 10^{-4}}

= 0.05 T

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Since the centre of the earth's magnetic field is given to be equal to the magnetic field produced by the wire, then:

the earth's magnetic field = 50000 μT

5 0
2 years ago
How much heat do you need to raise the temperature of 150 g of oxygen from -30c to -15c?
Naddika [18.5K]
The amount of heat needed to raise the temperature of a substance by \Delta T is given by
Q=m C_s \Delta T
where
m is the mass of the substance
Cs is its specific heat capacity
\Delta T is the increase in temperature

For oxygen, the specific heat capacity is approximately 
C_s = 0.92 J/(g K)
The variation of temperature for the sample in our problem is 
\Delta T= -15^{\circ}C-(-30^{\circ} C)=+15^{\circ}C=15 K
while the mass is m=150 g, so the amount of heat needed is
Q=m C_s \Delta T=(150 g)(0.92 J/g K)(15 K)=2070 J
4 0
3 years ago
Read 2 more answers
In any system, the _____ in the system remains constant, while the PE or KE may change.
vladimir1956 [14]

Answer:

The sum of PE and KE remains constant

Explanation:

6 0
3 years ago
You do 45.0 joules of work and 3.00 seconds how much power do you use​
Arada [10]

Answer:

15 watt

Explanation:

Power is the rate at which work is done.

This means you divide the work done with the amount of time used to perform the work.

The formula for Power is : P = W/t  where;

W= work done in J = 45

t= time in seconds = 3 sec

P= 45/ 3 = 15 watt

8 0
2 years ago
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