1 mole of h3bo3...........6.023*10²³ each h and B and 0 so we will have 3hydrogen+ 1 B+3 oxygen = 7*6.023*10²³ atoms
1 mole .......7*6.023*10²³atoms
4 moles ........x atoms
x=4*7*6.023*10²³.
Answer:
Your answer is C
Explanation:
When an acid and base react, the acidic hydrogen ion and the basic hydroxide ion in each acid and base neutralize each other and form water. Meanwhile the conjugate base and conjugate acid (the leftover compounds) react to form an ionic molecule, or a salt. (In chemistry, when an anion and a cation form an ionic bond the new molecule is called a salt). Hope this helps!
The specific heat means the heat absorbed when 1 g of the compound increase 1 ℃. So the specific heat is 41.71/(18.69*17)=0.131 J/(g*k).
Answer:
The answer to your question is 40 L of NH₃
Explanation:
Data
Volume of NH₃ = x
mass of N₂ = 25 g
mass of H₂ = excess
Balanced chemical reaction
N₂ + 3H₂ ⇒ 2NH₃
Process
1.- Find the molar mass of N₂ and NH₃
N₂ = 14 x 2 = 28g
2NH₃ = 2[ 14 + 3] = 34 g
2.- Write a proportion to solve this problem
28 g of N₂ --------------- 34 g of NH₃
25 g of N₂ ------------- x
x = (25 x 34)/28
x = 30.36 g of NH₃
3.- Calculate the volume of NH₃
17 g of NH₃ -------------- 22.4 L
30.36 g of NH₃ -------- x
x = (30.36 x 22.4) / 17
x = 40 L