Answer:
Use the Bromotriflouride catalyst, BF₃
Explanation:
The BF₃ is most likely to yield less desired side products. The effect lies in the reaction mechanism.
BF₃ is a Lewis acid. Its role is to promote the ionization of the HF. This is achieved through the electrophilic mechanism. The reaction mechanism is as follows:
2 - methylpropene + H-F-BF₃ → H-F + H₃C + benzene
butylbenzene + F-BF₃ → tert-butylbenzene + H-F + BF₃ (regenerated catalyst)
Answer:THINNER contains more effective for measurin
Explanation:
Answer:
NH4Cl > Li2SO4 > CoCl3
Explanation:
Let us recall that the freezing point depression depends on the molality of the solution and the number of particles present.
Let us also recall that freezing point depression is a colligative property. It depends on the number of particles present in solution.
Usually, the more the number of particles present, the lower the freezing point. Hence, NH4Cl which has only two particles will have the highest freezing point while CoCl3 which has four particles will have the lowest freezing point.
Answer:

Explanation:
To convert from grams to moles, we must use the molar mass. This can be found on the Periodic Table. First, find the molar mass of iron and chlorine.
- Fe: 55.84 g/mol
- Cl: 35.45 g/mol
Check the formula. There is a subscript of 3 after Cl, so there are 3 atoms of chlorine in 1 molecule. Multiply iron's molar mass by 3, then add iron's molar mass.
- FeCl₃: 55.84 + 3(35.45) = 55.84+106.35=162.19 g/mol
Use this number as a ratio.

Multiply by the given number of grams.

Flip the ratio so the grams of iron (III) chloride cancel.




The original measurement of grams has 5 significant figures, so our answer must have the same. For the number we calculated, that is the ten thousandth place.

258.45 grams is approximately 1.5935 moles of iron (III) chloride.
Answer:
Molecular formula = S₂O
₆
Explanation:
Given data:
Empirical formula = SO₃
Molecular formula = ?
Molecular mass = 152 g/mol
Solution:
Molecular formula = n (empirical formula)
n = molar mass of compound / empirical formula mass
Empirical formula mass = 80 g/mol
n = 152 g/mol / 80 g/mol
n = 2
Molecular formula = n (empirical formula)
Molecular formula = 2(SO₃)
Molecular formula = S₂O
₆