Given: V of cube = 4s^2, where s is the length of just one edge of the cube.
I think second must b the answee
60/150 = 40%
Hope this helps :D
m GH = 57''
________
tan 39° = opposite / adjacent
tan 39° = m GH / m HJ
tan 39° * m HJ = m GH
m HJ = m GH / tan 39°
m HJ ≈ 57'' / 0.810
m HJ ≈ 70.4'' <——<span>— measure of the segment HJ</span>
________
sin 39° = opposite / hypotenuse
sin 39° = m GH / m GJ
sin 39° * m GJ = m GH
m GJ = m GH / sin 39°
m GJ = 57'' / 0.629
m GJ ≈ 90.6'' <——— measure of the segment GJ
________
So the perimeter is
p = m GH + m HJ + m GJ
p = 57'' + 70.4'' + 90.6''
p = 218'' <——<span>— this is the answer.</span>
I hope this helps. =)
Tags: <em>perimeter right triangle sine cosine tangent sin cos tan trig trigonometry geometry</em>
