Answer:
first option
Step-by-step explanation:
If ( x + h) is a factor of f(x) then f(- h) = 0 , then
If (x + 1) is a factor of f(x) then f(- 1) = 0
f(- 1) = 7 - 5(- 1)³ - 10(- 1)² + 2(- 1)
= 7(1) - 5(- 1) - 10(1) - 2
= 7 + 5 - 10 - 2
= 12 - 12
= 0
Since f(- 1) = 0 then (x + 1) is a factor of f(x)
Solve the following system using elimination:
{y = 4050 x + 2949 | (equation 1)
{y = 5165 x + 93 | (equation 2)
Express the system in standard form:
{-(4050 x) + y = 2949 | (equation 1)
{-(5165 x) + y = 93 | (equation 2)
Swap equation 1 with equation 2:
{-(5165 x) + y = 93 | (equation 1)
{-(4050 x) + y = 2949 | (equation 2)
Subtract 810/1033 × (equation 1) from equation 2:
{-(5165 x) + y = 93 | (equation 1)
{0 x+(223 y)/1033 = 2970987/1033 | (equation 2)
Multiply equation 2 by 1033:
{-(5165 x) + y = 93 | (equation 1)
{0 x+223 y = 2970987 | (equation 2)
Divide equation 2 by 223:
{-(5165 x) + y = 93 | (equation 1)
{0 x+y = 2970987/223 | (equation 2)
Subtract equation 2 from equation 1:
{-(5165 x)+0 y = (-2950248)/223 | (equation 1)
{0 x+y = 2970987/223 | (equation 2)
Divide equation 1 by -5165:
{x+0 y = 2856/1115 | (equation 1)
{0 x+y = 2970987/223 | (equation 2)
Collect results:
Answer: {x = 2856/1115 , y = 2970987/223
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Solve the following system using substitution:
{y = 4050 x + 2949
{y = 5165 x + 93
Substitute y = 4050 x + 2949 into the second equation:
{y = 4050 x + 2949
{4050 x + 2949 = 5165 x + 93
In the second equation, look to solve for x:
{y = 4050 x + 2949
{4050 x + 2949 = 5165 x + 93
Subtract 5165 x + 2949 from both sides:
{y = 4050 x + 2949
{-1115 x = -2856
Divide both sides by -1115:
{y = 4050 x + 2949
{x = 2856/1115
Substitute x = 2856/1115 into the first equation:
{y = 2970987/223
{x = 2856/1115
Collect results in alphabetical order:
Answer: {x = 2856/1115, y = 2970987/223
15/18.. both are divisible by 3 so therefore you can reduce the fraction to 5/6
Answer:
9
Step-by-step explanation:
18 is the diameter and half of that would be 9