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ANEK [815]
3 years ago
5

Find the solution to the system of equations.y=2x+3 and y=-3x+3

Mathematics
1 answer:
iragen [17]3 years ago
6 0

Answer:

x = 0 and y = 3

Step-by-step explanation:

Using elimination method, we can solve for x and y in the simultaneous equation

y = 2x + 3   .................................eqn 1

y = -3x + 3  .................................eqn 2

multiply equation 1 by 3 and equation 2 by 2, then we will have

(y = 2x + 3) × 3

(y = -3x + 3) × 2

3y = 6x + 9   ...............................eqn 3

2y = -6x + 6 ................................eqn 4

Add eqn 3 and 4 together and we will eliminate x and have

5y = 15

Divide both sides by 5, and we will have

y = 3

To solve for x, substitute 3 for y in eqn 1

y = 2x + 3

3 = 2x + 3

collect like terms

3 - 3 = 2x

0 = 2x

Therefore x = 0

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Answer:

Minimum = 64

Maximum = 727

Medium = 200

Mean = 277.667

Mode = none

<em>s</em><em> </em>= 223.825

<em>Q</em><em> </em>= 211.024

<em>n</em><em> </em>= 9

8 0
3 years ago
Y=x+12 please answer quickly and plus i need 20 characters<br>​
snow_tiger [21]

Answer:

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5 0
3 years ago
Who knows how to do this ughhh I need help!
suter [353]

Answer:

\large\boxed{\sqrt{56x^{17}}=2x^8\sqrt{14x}}

Step-by-step explanation:

Domain:\ x\geq0\\\\\sqrt{56x^{17}}=\sqrt{4\cdot14\cdot x^{16+1}}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\sqrt{4\cdot14\cdot x^{16}\cdot x^1}\\\\\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt4\cdot\sqrt{14}\cdot\sqrt{x^{16}}\cdot\sqrt{x}=2\cdot\sqrt{14}\cdot\sqrt{x^{8\cdot2}}\cdot\sqrt{x}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=2\cdot\sqrt{14}\cdot\sqrt{(x^8)^2}\cdot\sqrt{x}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=2\cdot\sqrt{14}\cdot x^8\cdot\sqrt{x}=2x^8\sqrt{14x}

8 0
3 years ago
A student got 22 out of 25 questions correctly, shade the model to help write the decimal that repersents the fraction of correc
IrinaK [193]

Answer:

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Cross multiply and you will have:

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Step-by-step explanation:


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3 years ago
0.3(3a-4)-0.05(8a)(-7a)
Anit [1.1K]

Answer:

2.8a²+0.9a - 1.2

Step-by-step explanation:

Given the expression 0.3(3a-4)-0.05(8a)(-7a)

Expand using the distributive law

0.3(3a-4)-0.05(8a)(-7a)

0.3(3a)-0.3(4)-0.05(8a)(-7a)

0.9a-1.2 - 0.05(8a)(-7a)

0.9a - 1.2 + 2.8a²

Rearrange

2.8a²+0.9a - 1.2

Hence the required expression is 2.8a²+0.9a - 1.2

3 0
2 years ago
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