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1 year ago

Calculate the molality of a solution containing 15.01 g of glycerol (c 3h 8o 3) in 42.3 g of ethanol (c 2h 5oh).

Chemistry

1 answer:

kkurt [141]1 year ago

7 0

The molality of the glycerol solution is 3.854mol/kg

The number of moles of solute present in a solution equal to 1 kg or 1000 g of solvent is referred to as its molality.

Given:

Mass, m1 of glycerol = 15.01g

Mass, m2 of ethanol = 42.3g

Molar mass, mm1 of glycerol = 92.095g/mol

Molar mass, mm2 of ethanol = 46.069g/mol

To find:

Molality, m = ?

Formula:

Molality, m = moles of solute / kg of solvent

Calculations:

No. of moles of glycerol = 15.01 x (1/92.095)

n = 0.163 mols

Molality, m = 0.163 / 0.0423g

Molality, m = 3.854mol/kg

Result:

3.854mol/kg is the molality of the glycerol solution.

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