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OlgaM077 [116]
3 years ago
8

There are 60 dogs at a doggie daycare one Friday. If 1/3 of the dogs are large dogs, 1/6 of the dogs are medium-sized dogs, whic

h statement is true
and the remaining dogs are small dogs, which statement is true?

A. There are 10 less large dogs than small dogs at the daycare.

B. There are 10 more large dogs than small dogs at the daycare

C. There are 20 less dogs than small dogs at the daycare.

D. There are 20 more large dogs than small dogs at the daycare .
Mathematics
2 answers:
ehidna [41]3 years ago
4 0

Answer:

Step-by-step explanation:

D

aivan3 [116]3 years ago
4 0

Answer:

I think its B

Hope this helps

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Can you help givie full info thanks
liubo4ka [24]

Answer:

13

Step-by-step explanation:

Using long division, you can multiply each given value by 100 to eliminate the decimals:

2.08x100=208

0.16x100=16

OR (calculator method)

2.08÷0.16=13

You must divide the amount of food per cat by the total amount of food available to determine how many cats can be fed.  This division can be done using a calculator.

OR

5 0
2 years ago
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2. Explain, in words, how you would solve this problem. Hint: you should get 1 point
makkiz [27]

Answer:

9-24=4(3)

-15=4×3

-15=12

7 0
3 years ago
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Molly had a balance of $72 In her savings account before depositing $25. What is her new balance?
vovangra [49]

Answer:

$97

Step-by-step explanation:

just add 72 and 25 dude

4 0
3 years ago
If a woodchuck could chuck 2<br> pieces of wood every hour, how big is a beavers dam?
Nataly_w [17]

Answer:

How many hours?

Step-by-step explanation:

the answer to this is 2x

X is the number of hours and you multipy it by 2 wood

6 0
4 years ago
WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!
Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: a^2-b^2=(a+b)(a-b)

Given  x^2-16=0

Rewrite 16 as 4²

Therefore, a^2=x^2 and b^2=4^2

\implies a = \sqrt{x^2}=x

\implies b=\sqrt{4^2} =4

\implies x^2-16^2=(x+4)(x-4)

\implies (x+4)(x-4)=0

\implies (x+4)=0 \implies x=-4

\implies (x-4)=0 \implies x=4

<u>Method 2</u>

Given equation:

x^2-16=0

Add 16 to both sides:

\implies x^2-16+16=0 + 16

\implies x^2=16

Square root both sides:

\implies \sqrt{x^2}=\sqrt{16}

\implies x=\pm4

Therefore, x = -4, x = 4

6 0
2 years ago
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