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OlgaM077 [116]
3 years ago
8

There are 60 dogs at a doggie daycare one Friday. If 1/3 of the dogs are large dogs, 1/6 of the dogs are medium-sized dogs, whic

h statement is true
and the remaining dogs are small dogs, which statement is true?

A. There are 10 less large dogs than small dogs at the daycare.

B. There are 10 more large dogs than small dogs at the daycare

C. There are 20 less dogs than small dogs at the daycare.

D. There are 20 more large dogs than small dogs at the daycare .
Mathematics
2 answers:
ehidna [41]3 years ago
4 0

Answer:

Step-by-step explanation:

D

aivan3 [116]3 years ago
4 0

Answer:

I think its B

Hope this helps

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<h3>52.68 feet per hour = 10.536 inches per minutes</h3>

<h3>Further explanation</h3>

Acceleration is rate of change of velocity.

\large {\boxed {a = \frac{v - u}{t} } }

\large {\boxed {d = \frac{v + u}{2}~t } }

<em>a = acceleration ( m/s² )</em>

<em>v = final velocity ( m/s )</em>

<em>u = initial velocity ( m/s )</em>

<em>t = time taken ( s )</em>

<em>d = distance ( m )</em>

Let us now tackle the problem !

1 ~ foot = 30.48 ~ cm

1 ~ inch = 2.54 ~ cm

1 ~ foot = 12 ~ inches

\boxed {52.68 ~ feet = 52.68 \times 12 ~ inches = 632.16 ~ inches}

1 ~ day = 24 ~ hours

\boxed {1 ~ hour = 60 ~ minutes}

If the dwarf seahorse hippocampus zosterae swims at a rate of 52.68 feet per hour , then :

52.68 ~ feet/h = \frac{52.68 ~ feet}{1 ~ hour}

52.68 ~ feet/h = \frac{52.68 \times 12 ~ inches}{60 ~ minutes}

52.68 ~ feet/h = \frac{632.16 ~ inches}{60 ~ minutes}

\large {\boxed {52.68 ~ feet/h = 10.536 ~ inches/min} }

<h3>Learn more</h3>
  • Velocity of Runner : brainly.com/question/3813437
  • Kinetic Energy : brainly.com/question/692781
  • Acceleration : brainly.com/question/2283922
  • The Speed of Car : brainly.com/question/568302

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Kinematics

Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate

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