Quantity of charge unloaded = 51.9 Coulombs
Potential difference = 10.93 megavolts = 1.093 x 10⁷ volts
1 volt = 1 joule per coulomb
1.093 x 10⁷ volts = 1.093 x 10⁷ joules per coulomb
Energy = (1.093 x 10⁷ J/C) x (51.9 C)
Energy = 567.267 megaJoules
That's <em>5.67 x 10⁸ Joules</em> .
==> My wife's blow-dryer is marked 1260 watts.
If the energy in this lightning strike could be collected, bottled, stored, and used as needed, it could run my wife's blow-dryer for 125 hours. That would save us more than $30 on our electric bill !
skill related components of fitness are .
Agility.
Balance.
Coordination (hand-eye and/or foot-eye)
Power.
Reaction time.
Speed.
Answer: The acceleration results if a net force of 4F acts on a mass of 6m is 2/3a.
Explanation:
Force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is:
F= mass( kg) × acceleration( m/ s²)
Acceleration is defined as the rate at which the velocity of an object changes. From the formula of force given above it can be determined by making it the subject of formula. Therefore acceleration= Force/ mass.
From the question,
Force= 4F
Mass= 6m
Therefore acceleration= F/m
= 4/6
Acceleration= 2/3a
For an uniformly accelerated motion, the final velocity is given by:

where vi is the initial speed, a is the acceleration, and t the time interval.
In our problem,

,

(with negative sign, because the car is decelerating), and

. Substituting,
Answer:
7 deg
Explanation:
= mass of the rod = 
= weight of the rod = 
= spring constant for left spring = 
= spring constant for right spring = 
= stretch in the left spring
= stretch in the right spring
= length of the rod = 0.75 m
= Angle the rod makes with the horizontal
Using equilibrium of force in vertical direction for left spring

Using equilibrium of force in vertical direction for right spring

Angle made with the horizontal is given as
