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ZanzabumX [31]
3 years ago
11

Another name for Newton’s 2nd law

Physics
1 answer:
monitta3 years ago
4 0
According to Newton’s second law of motion, also know as the law of force and Accelerate , a force upon an object causes it to accelerate according to the formula net force = mass x acceleration
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tia_tia [17]

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How can shoe and tire marks be preserved in mud?
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The answer is A) Casting
7 0
3 years ago
NEED HELP ASAP!!!
Anna [14]

A.)the downward force on the floor is equal to the upward force on his feet

Explanation:

When a basketball player jumps to make a shot, the downward force on the floor is equal to the upward force on his feet. This is according to the newton's law of motion.

Newton's law of motion states that "action and reaction are equal and opposite in direction."

  • The downward force is the force exerted by his feet for the jump.
  • The upward force is the force exerted by the floor to aid is jump.
  • We see that both the upward and downward forces are in opposite direction.
  • The net force allows the basketball player to effectively jump

Learn more:

Newton's law of motion brainly.com/question/11411375

#learnwithBrainly

6 0
3 years ago
Which of the following require friction?
Bess [88]

Explanation:

Option D all of the above

if this helps you then please make me brainlist

7 0
2 years ago
A proton travels through uniform magnetic and electric fields. The magnetic field is in the negative x direction and has a magni
Andreyy89

Answer:

a) F = 2.13 \cdot 10^{-18} N

b) F = 3.65 \cdot 10^{-19} N

c) F = 1.53 \cdot 10^{-18} N  

Explanation:

We have:                    

B: is the magnetic field = (2.66x10⁻³ T)(-\hat{\imath})      

v: is the velocity of the proton = (2930 m/s)\hat{\jmath}    

a) To find the magnitude of the net force (F) we need to use the Lorentz force equation:

\vec{F} = q(\vec{E} + \vec{v}\times \vec{B})  (1)

E: is the electric field = (5.51 V/m)\hat{k}            

q: is the proton charge = 1.6x10⁻¹⁹ C

\vec{F} = 1.6\cdot 10^{-19}(5.51 \hat{k} + 2930 \hat{\jmath}\times 2.66\cdot 10^{-3}(-\hat{\imath})) = 1.6\cdot 10^{-19}(5.51 \hat{k} + 7.79 \hat{k}) = (2.13 \cdot 10^{-18} N)\hat{k}                                                                                            

Hence, the magnitude of the net force is:

F = \sqrt{F_{x}^{2} + F_{y}^{2} + F_{z}^{2}} = \sqrt{0 + 0 + (2.13 \cdot 10^{-18}\hat{k})^{2}} = 2.13 \cdot 10^{-18} N

b) When E = (5.51 V/m)(-\hat{k}), the net force is (equation 1):

\vec{F} = 1.6\cdot 10^{-19}[5.51(-\hat{k}) + 2930 \hat{\jmath}\times 2.66\cdot 10^{-3}(-\hat{\imath})] = 1.6\cdot 10^{-19}[5.51(-\hat{k}) + 7.79 \hat{k}] = (3.65 \cdot 10^{-19} N)\hat{k}                     

Then, the magnitude of the net force is:

F = \sqrt{0 + 0 + (3.65 \cdot 10^{-19}\hat{k})^{2}} = 3.65 \cdot 10^{-19} N    

c) When E = (5.51 V/m)(\hat{\imath}), the net force is:  

\vec{F} = 1.6\cdot 10^{-19}(5.51\hat{\imath} + 2930 \hat{\jmath}\times 2.66\cdot 10^{-3}(-\hat{\imath})) = 1.6\cdot 10^{-19}(5.51\hat{\imath} + 7.79 \hat{k}) = 8.82 \cdot 10^{-19}\hat{\imath} + 1.25 \cdot 10^{-18}\hat{k}                                            

Hence, the magnitude of the net force is:

F = \sqrt{(8.82 \cdot 10^{-19}\hat{\imath})^{2} + 0 + (1.25 \cdot 10^{-18}\hat{k})^{2}} = 1.53 \cdot 10^{-18} N  

I hope it helps you!                                                                                                

5 0
3 years ago
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