The terminal speed of the marble is 0.588 m/s.
<h3>Calculation:</h3>
We know that,
F = mg ......(1)
where,
F = force
m = mass
g = acceleration due to gravity
Also,
v = F/k ......(2)
where,
v = terminal speed
k = proportionality constant
Substituting the value of F from equation (1) in equation (2)
v = mg/k .......(3)
Given,
m = 30 g = 0.030 kg
k = 0.500 kg/s
g = 9.8 m/s²
To find,
v =?
Put the values in equation (3)
v = mg/k
v = 0.03(9.8)/ 0.500
= 0.294/0.500
= 0.588 m/s
Hence, the terminal speed of the marble is 0.588 m/s.
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The answer is voice onset time. It is a part of the production of stop consonants. Its definition is the length of time that passes between the release of a stop consonant and the start of the voicing and the vibration of the vocal folds.
Answer: Both Technician A and B are right.
Explanation:
Both Technicians are correct. when a valve remains open as it approaches the TDC(top dead center), they piston may strike the valve which would result to damage of the engine. Same applies when it is open as it approaches the top dead center as a valve train damage may occur. As the driven train is responsible for providing power to the wheels from the engine block.
An upright base / 6ft long
