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Ann [662]
3 years ago
15

A single conservative force Fx = (6.0x  12) N (x is in m) acts on a particle moving along the x axis. The potential energy asso

ciated with this force is assigned a value of +20 J at x = 0. What is the potential energy at x = 3.0 m?
Physics
1 answer:
jasenka [17]3 years ago
6 0

Answer:

U(3)=-43J

Explanation:

Potential energy is minus the integral of Fdx.  Doing the integration yields:

U=\int\limits {6.0x+12}\, dx

U=-3x^2-12x+C

U(0)=20J

so

U(0)=-3(0)^2+12(0)+C=20

C=20

Now for x=3.0m

U(3)=-3*(3)^2-12(3)+20

U(3)=-43J

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