When a small cart collide with a large mass then during collision they must be in contact with each other for some interval of time
During this contact interval we can say they will exert normal force on each other
This normal force is always equal and opposite on two balls which means this force will follow Newton's III law
It will be same in magnitude but opposite in the direction
So here correct answer would be
<u><em>They both experience the same magnitude of the collision force.</em></u>
Answer:
Explanation:
Work is equal to the product of force and distance.
We are solving for the distance, d. We know the force is 596.82 Newtons and the work is 35,674.7 Joules.
- If we convert the units for Joules, the problem will be simpler later.
- 1 Joule is equal to 1 Newton meter.
- The work done by the runner, 35,674.7 J, equals 35,674.7 N*m
Substitute the values into the formula.
We want to solve for the distance, so we must isolate d on one side of the equation.
d is being multiplied by 596.82 Newtons. The inverse of multiplication is division. Divide both sides of the equation by 596.82 N
The Newtons will cancel, hence the prior unit conversion.
Let's round to the nearest hundredth, so the answer is concise. The 4 in the thousandth place tells us to leave the 7 in the hundredth place.
The distance covered during the portion of the race is about <u>59.77 meters.</u>
<h3>Answer: 2 seconds</h3>
This problem is equivalent to kicking the ball 8 m/s and it rolls to a point 16 meters away, and everything is on a flat ground (with no cliff). This is because the horizontal component of the velocity does not get affected by how tall the cliff is and the force of gravity. Note how the height of the cliff isn't even mentioned. So that's a clue that we can ignore it.
If x is the number of seconds, then 8x is the distance in meters it travels. So we have 8x = 16 solve to x = 2. The ball travels for 2 seconds before reaching its target.
Answer:
Yes,the law of conservation of momentum is satisfied.The momentum before the collision is 1.5 kg.m/s and the total momentum after the collision is 1.5kg.m/s.The momentum before and after the collision is the same.