1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
NARA [144]
3 years ago
5

Equilibrium of forces

Physics
2 answers:
tensa zangetsu [6.8K]3 years ago
7 0

Answer:

<em><u>If the size and direction of the forces acting on an object are exactly balanced, then there is no net force acting on the object and the object is said to be in equilibrium. Because the net force is equal to zero, the forces in Example 1 are acting in equilibrium.</u></em>

Alinara [238K]3 years ago
7 0

Equilibrium of forces means that the net force is 0. It can either be when there is no force acting on the object or when the force acting on the object are balanced.

You might be interested in
Read the paragraph, and then answer the question.
dem82 [27]

Cryosphere

<h2><em><u>H</u></em><em><u>o</u></em><em><u>p</u></em><em><u>e</u></em><em><u> </u></em><em><u>I</u></em><em><u>t</u></em><em><u> </u></em><em><u>H</u></em><em><u>e</u></em><em><u>l</u></em><em><u>p</u></em><em><u>s</u></em><em><u> </u></em><em><u>Y</u></em><em><u>o</u></em><em><u>u</u></em><em><u>!</u></em></h2>

3 0
3 years ago
Read 2 more answers
Particles of mass 3m and 5m hang one at each end of a light inextensible string which passes over a pulley.the system is release
Serggg [28]

Answer:

36.8 N

Explanation

tension in string when both bodies move vertically is given as

T = (m1 × m2 × g) / ( m1 +m2)

T = (5 × 3 × 9.81)/(5+3)

T = 147.15/8

T = 18.39375

SINCE TENSIONS ARE ON BOTH SIDES OF PULLEY AND ON PULLEY BOTH ARE DIRECTED DOWNWARD

HENCE FORCE ON PULLEY = 2 × T

                                               = 2×18.39375

                                               = 36.7875

                                                 = 36.8 N

5 0
3 years ago
Two horses are pulling a barge with a mass 2000 kg along a canal. The cable connected to the first horse makes an angle of θ1= 4
Shkiper50 [21]

Answer:

a = 0.5195 m/s²

θ = 9.997º ≈ 10º

Explanation:

We apply Newton's 2nd Law as follows:

∑ Fx = m*ax

∑ Fy = m*ay

Then we have

∑ Fx = F₁x + F₂x = m*ax    ⇒ 600*Cos 40º + 600*Cos (-20º) = 2000*ax

⇒   ax = 0.5117 m/s²

∑ Fy = F₁y + F₂y = m*ay    ⇒ 600*Sin 40º + 600*Sin (-20º) = 2000*ay

⇒   ay = 0.0902 m/s²

the magnitude of the acceleration of the barge is

a = √(ax² + ay²) = √((0.5117 m/s²)² + (0.0902 m/s²))= 0.5196 m/s²

and the direction is

θ = Arctan (ay / ax) = Arctan (0.0902 / 0.5117) = 9.997º ≈ 10º

8 0
3 years ago
A student measured the density of Galena to be 7.9g/cm3 however the known density of Galena is 7.6g/cm3 . Calculate the percent
VLD [36.1K]
7.9/7.6-1=3.9%
.............
6 0
3 years ago
Read 2 more answers
A 0.40 kg ball is suspended from a spring with spring constant 12 n/m . part a if the ball is pulled down 0.20 m from the equili
PolarNik [594]
The total mechanical energy of the system at any time t is the sum of the kinetic energy of motion of the ball and the elastic potential energy stored in the spring:
E=K+U= \frac{1}{2}mv^2+ \frac{1}{2}kx^2
where m is the mass of the ball, v its speed, k the spring constant and x the displacement of the spring with respect its rest position.

Since it is a harmonic motion, kinetic energy is continuously converted into elastic potential energy and vice-versa.

When the spring is at its maximum displacement, the elastic potential energy is maximum (because the displacement x is maximum) while the kinetic energy is zero (because the velocity of the ball is zero), so in this situation we have:
E=U_{max}= \frac{1}{2}k(x_{max})^2

Instead, when the spring crosses its rest position, the elastic potential energy is zero (because x=0) and therefore the kinetic energy is at maximum (and so, the ball is at its maximum speed):
E=K_{max}= \frac{1}{2}m(v_{max})^2

Since the total energy E is always conserved, the maximum elastic potential energy should be equal to the maximum kinetic energy, and so we can find the value of the maximum speed of the ball:
U_{max}=K_{max}
\frac{1}{2}k(x_{max})^2 =  \frac{1}{2}m(v_{max})^2
v_{max}= \sqrt{ \frac{k x_{max}^2}{m} }= \sqrt{ \frac{(12 N/m)(0.20 m)^2}{0.4 kg} }=1.1 m/s
3 0
3 years ago
Other questions:
  • PLEASE HURRY THIS IS URGENT
    8·1 answer
  • Compare landslides and slumps.
    6·2 answers
  • Which one of the following is NOT an evidence of the Big Bang Theory? A. most objects in space are moving away from one another
    14·1 answer
  • Lesson 8 Exit Ticket
    11·1 answer
  • How do you do 12, 13, and 14?
    14·1 answer
  • A man runs at a speed of 6.25 meters per second for 240 seconds. How 5 po
    9·1 answer
  • the resistivity of a given wire of cross session area 0.7mm² is 49×10⁴.calcuate the resistance of a 2m lenght of wire​
    14·1 answer
  • Which of the following is the ability of a physical system to do work?
    8·1 answer
  • Calculate the frequency of an electromagnetic wave having a wavelength of 60 m.​<br><br>Help Please​
    5·1 answer
  • Pa help po science po Ito please​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!