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3 years ago

Microwelds are formed where

Physics

2 answers:

Jlenok [28]3 years ago

8 0

Between the bumps and dips of two surfaces. SO the answer is 2 surfaces. Hope this helps! :)

kvv77 [185]3 years ago

8 0

Answer:

Bumps from the two surfaces come into contact.

Explanation:

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A person rolls a barrel up an inclined plane with a length of 6m and a height of 3m/ How much force is needed to roll up the bar

snow_lady [41]

Answer:

Length (l) = 6 m

height (h) = 3 m

Load(L) = 500 N

Effort (E) = ?

we know the principal that

E * l = L * h

6 E = 500 * 3

6E = 1500

E = 250

therefore 250 N work is done on the barrel.

8 0

4 years ago

How fast is a car going in m/5 if speedometer reads 45 miles?

fredd [130]

Answer:

i think you would have to divide to 2 numbers to get the sum

Explanation:

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3 years ago

Electromagnetic spectrum, i need help putting them in order. And maybe get a little help understanding this subject

umka2103 [35]

Explanation:

In order from highest to lowest energies the parts of electromagnetic spectrum are named as

Gamma rays,

X-rays,

ultraviolet radiation,

visible light,

infrared radiation,

and radio waves.

Microwaves are a subsections of radio waves. They are used in microwave ovens to heat the food items.

This is expected EM spectrum in field of science.

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3 years ago

PLZ HELP Lab: Circuit Design

Masteriza [31]

Answer:

Explanation:

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3 years ago

The gravitational attraction between a 20 kg cannonball and a 0.002 kg

Naya [18.7K]

Answer:

$2.966\times 10^{-11}\ N$

Explanation:

Given:

Mass of the cannonball (M) = 20 kg

Mass of the marble (m) = 0.002 kg

Distance between the cannonball and marble (d) = 0.30 m

Universal gravitational constant (G) = $6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2}$

Now, we know that, the gravitational force (F) acting between two bodies of masses (m) and (M) separated by a distance (d) is given as:

$F=\dfrac{GMm}{d^2}$

Plug in the given values and solve for 'F'. This gives,

$F=\frac{(6.674\times 10^{-11}\ m^3 kg^{-1} s^{-2})\times (20\ kg)\times (0.002\ kg)}{(0.30\ m)^2}\\\\F=\frac{6.674\times 20\times 0.002\times 10^{-11}\ m^3 kg^{-1+2} s^{-2}}{0.09\ m^2}\\\\F=2.966\times 10^{-11}\ kg\cdot m\cdot s^{-2}\\\\F=2.966\times 10^{-11}\ N.........(1\ N = 1\ kg\cdot m\cdot s^{-2})$

The same force is experienced by both cannonball and marble.

Therefore, the gravitational force of the marble is $2.966\times 10^{-11}\ N$

3 0

3 years ago