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castortr0y [4]
3 years ago
8

Microwelds are formed where

Physics
2 answers:
Jlenok [28]3 years ago
8 0

Between the bumps and dips of two surfaces. SO the answer is 2 surfaces. Hope this helps! :)

kvv77 [185]3 years ago
8 0

Answer:

Bumps from the two surfaces come into contact.

Explanation:

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How do t cells differ from b cells
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for more info , comment !
5 0
3 years ago
Why would a soccer ball keep going forever without physics? Pls help and explain why
Pani-rosa [81]
A soccer ball would keep moving forever without physics, because without force to act upon the soccer ball, it could, or will not be able to stop the acceleration. And force is a factor in physics.
7 0
3 years ago
Read 2 more answers
The velocity as a function of time of a moving particle is given by v = α+ βt2 , where α and β are constants and t is time in s.
marin [14]

The acceleration of the particle at 3s is [tex]a = 6 \beta [/tex]

v  =  \alpha  +  \beta {t}^{2}

<h3>How to calculate acceleration </h3>

a =  \frac{dv}{dt} \\ v =  \alpha  +  \beta  {t}^{2} \\ \frac{dv}{dt}  = 0 + 2 \beta t \\

if Time is given as 3s

therefore, Acceleration is

a = 2 \beta t \\ a = 2 \beta 3 \\ a = 2 \times  \beta  \times 3 \\ a = 6 \beta

Acceleration is

a = 6 \beta

Read more about velocity:

brainly.com/question/19365526

6 0
2 years ago
Explain the application of pascals law<br>​
Marta_Voda [28]

Answer:

pplications of Pascal’s Law  

Hydraulic Lift: The image you saw at the beginning of this article is a simple line diagram of a hydraulic lift. This is...

The construction is such that a narrow cylinder (in this case A) is connected to a wider cylinder (in this case B). They...

Pressure applied at piston A is transmitted equally to piston B without diminishing, on use of an incompressible fluid.

Explanation:

6 0
3 years ago
1. Is the sequence geometric? If so, identify the common ratio.
frozen [14]
1) <span>yes;2 6*2=12 12*2=24 24*2=48
2)</span><span>Next Term (or nth term) = ar^n-1 
</span>
a = first term, i.e. 5 
<span>r = common ratio i.e. 3 (as 15/5=3 and 45/15=3 </span>
<span>n = .. </span>
<span>as you already have 1st , 2nd and 3rd terms</span>
<span>substituting now </span>
<span>T4= ar^n-1 </span>
<span>= 5*3^4-1 </span>
<span>= 5*3^3 </span>
<span>= 5*27 </span>
<span>T4 = 135 
</span>T5= ar^n-1 
<span>= 5*3^5-1 </span>
<span>= 5*3^4 </span>
<span>= 5*81 </span>
<span>T5 = 405 </span>


6 0
3 years ago
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