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3 years ago

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124 students played a sport in the fall, and 76 students played a sport in the spring. What was the percent decrease of the stud

ents who played sports in the spring? Round your answer to the nearest tenth of a percent.

1 answer:

Alexeev081 [22]3 years ago

8 0

Answer:

5.7%

Step-by-step explanation:

subtract 124-76.

then, you would divide 76 by 124 to get a weird number so multiply that by 100 to get this.

5.64516129.

then rounding to the nearest tenth would be 5.7.

so i think it would be 5.7%.

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1 yard = 3 feet

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2 feet * 3 = 6 feet

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Space Shuttle Marion is observing the launch of a space

Vera_Pavlovna [14]

Using the slope concept, it is found that the shuttle traveled 3.2 miles while Marion was watching.

<h3>What is a slope?</h3>

The slope is given by the <u>vertical change divided by the horizontal change</u>, and it's also the tangent of the angle of depression.

Initially, the angle of elevation is of 16º, with an elevation of 1 mi, hence:

$\tan{16^\circ} = \frac{1}{x_1}$

$x_1 = \frac{1}{\tan{16^\circ}}$

$x_1 = 3.5$

Then, at the end, the angle will be of 74º, with the elevation remaining constant, hence:

$\tan{74^\circ} = \frac{1}{x_2}$

$x_2 = \frac{1}{\tan{74^\circ}}$

$x_2 = 0.3$

The distance is:

$d = x_1 - x_2 = 3.5 - 0.3 = 3.2$

The shuttle traveled 3.2 miles while Marion was watching.

More can be learned about the slope concept at brainly.com/question/18090623

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2 years ago

A simple random sample of 110 analog circuits is obtained at random from an ongoing production process in which 20% of all circu

telo118 [61]

Answer:

64.56% probability that between 17 and 25 circuits in the sample are defective.

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 110, p = 0.2$

So

$\mu = E(X) = np = 110*0.2 = 22$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{110*0.2*0.8} = 4.1952$

Probability that between 17 and 25 circuits in the sample are defective.

This is the pvalue of Z when X = 25 subtrated by the pvalue of Z when X = 17. So

X = 25

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{25 - 22}{4.1952}$

$Z = 0.715$

$Z = 0.715$ has a pvalue of 0.7626.

X = 17

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{17 - 22}{4.1952}$

$Z = -1.19$

$Z = -1.19$ has a pvalue of 0.1170.

0.7626 - 0.1170 = 0.6456

64.56% probability that between 17 and 25 circuits in the sample are defective.

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3 years ago

Can anybody help out this math question it’s about graph please

malfutka [58]

Neither one of the slopes are going to be minus. It means you are travelling backwards in time, which is wonderful if you are a sci-fi fan, but not so good if you are Sharon. A and D has Sharon going from 70 to 0. That can't be happening so both are wrong.

Now you have to decide between B and C. The intersection point has Sharon going upwards until she is 20. She started out at 70. The graph has John starting at 70. That's not right.

So we've eliminated A,D and now C.

The answer must be B. They meet when Sharon is 90 and John is about 22.5 which is what it should be.

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3 years ago