22.4 molecules are in 4.48 liters of CO 2
Molar mass of A l 2 (S O 4 ) 3 = 342.15 g/mol
7.2g/ 342.15 g/mol
you can get number of moles.
then multiply that by12
Answer:
4.34atm
Explanation:
The following data were obtained from the question:
P1 = 3.50 atm
T1 = 24°C = 24 +273 = 297K
T2 = 95°C = 368K
P2 =?
Using P1 /T1 = P2 /T2, we can obtain the new pressure as follows:
P1 /T1 = P2 /T2
3.5 / 297 = P2 / 368
Cross multiply to express in linear form:
297 x P2 = 3.5 x 368
Divide both side by the 297
P2 = (3.5 x 368) /297
P2 = 4.34atm
Therefore, the gas pressure in the container at 95°C will be 4.34atm
Answer:
S₁₂
Explanation:
The freezing point depression (ΔTf) is a colligative property that can be calculated using the following expression.
ΔTf = Kf × m
where,
Kf: freezing point depression
m: molality
ΔTf = Kf × m
m = ΔTf / Kf
m = 0.156 °C / (29.8 °C/m)
m = 5.23 × 10⁻³ m
The molality is:
m = moles of solute / kilograms of solvent
moles of solute = m × kilograms of solvent
moles of solute = 5.23 × 10⁻³ mol/kg × 0.5000 kg
moles of solute = 2.62 × 10⁻³ mol
1.00 g corresponds to 2.62 × 10⁻³ moles. The molar mass of Sₙ is:
1.00 g/2.62 × 10⁻³ mol = 382 g/mol
We can calculate n.
n = molar mass of Sₙ / molar mass of S
n = (382 g/mol) / (32.0 g/mol)
n = 11.9 ≈ 12
The molar formula is S₁₂.
Ca<span>2+</span> is less electro-positive than Mg2+. Therefore, CaO is less ionic than MgO. and in turn means that the O in CaO is more like O<span>2<span>– will react with H in H2O more so than O2- of MgO, because it is more ionic means O is strongly bonded to Mg compare to Ca</span></span>
