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prohojiy [21]
3 years ago
5

What mass of Ca(OH)2 is needed to make 1250ML of a .75M solution?

Chemistry
1 answer:
Setler79 [48]3 years ago
5 0

Answer:

69.4kg

Explanation:

mole =volume/1000 * mole conc.

=1250/1000 * 0.75

mole =0.9

:• mole =mass /molar mass

mass =0.9*[40+32+2]

=69.4kg

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An object has a mass of 45.0 g and a volume of 4.0 ml. what is its density?
andreev551 [17]

Answer:

The answer is

<h2>11.25 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass = 45 g

volume = 4 mL

Substitute the values into the above formula and solve for the density

We have

Density =  \frac{45}{4}

We have the final answer as

<h3>11.25 g/mL</h3>

Hope this helps you

4 0
3 years ago
What kind of bond is created by a week electrical attraction between polar molecules
Studentka2010 [4]

Answer : The dipole-dipole interaction.

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For better understanding, please refer the attachment.

8 0
3 years ago
Define equilibrium.<br><br> plz and thxxx
Serggg [28]

Answer:

Equilibrium is the state of balance. Where opposing forces cancel each other out and no changes are occurring.

<em>Good luck, hope this helps :)</em>

5 0
3 years ago
Read 2 more answers
Three metal spoons are on table. They are at room temperature. If the three spoons touch.
Alex
If the spoons touch, no heat will flow among the spoons because they are already in thermal equilibrium with each other. This is hinted by the statement "they are at room temperature" which means they all have the same temperature. Heat only flows when there is a difference in temperature.<span>
The answer will be </span><span>C. No heat will flow among the spoons
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5 0
3 years ago
Read 2 more answers
38. Identify the most important types of interparticle forces pres
zhannawk [14.2K]

Answer: im thinking its gonna be d.C2H6 and also

the explanation is on the research i had did before i had answered this question so i really hope this help :)

Explanation:

Ar = van de waals forces or london forces

C

H

4

= van de waals forces or london forces

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CO = permanent dipole-dipole interactions

HF = hydrogen bonding

N

a

N

O

3

= permanent dipole-dipole interactions

C

a

C

l

2

= van de waals forces or london forces

4 0
3 years ago
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