I need help with this problem

Question part points submissions used how many tangent lines to the curve y = x/(x + 1) pass through the point (1, 2)

BigorU [14]

Hello here is a solution
look graph :
the curve : color blue
the first tangent : y = 0.13x +1.87 color Pink
the second tangent : y = 1.88 x +0.14 color green

3 0

2 years ago

suppose you are in your last semester of college and have a 2.75 GPA after 105 credit hours if you are taking 15 credit hours in

Valentin [98]

Answer:

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

Step-by-step explanation:

Given,

CGPA = 2.75

Credit hours = 105

Last semester GPA = 4

Last semester credit hours = 15

CGPA = $\frac{sum of (Credit hours of each subject * GPA of each subject)}{Total credit hours}$ credit hours * gpa

in our case, it would be:

CGPA = $\frac{(2.75*105)+(4*15}{105+15}$

=> $\frac{(288.75)+(60)}{120}$

=> $\frac{348.75}{120}$

=> 2.90

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

7 0

3 years ago

write an equation to find the number of students in mr.boggs homeroom if the total number of stdents is 90

prohojiy [21]

The number of students in Mr. Boggs’s homeroom is equal to b. Add the total number of students in each class and set it equal to 90.

90 = b + 1.5(b + 2) + 15 + (2b – 9)

Use the Distributive Property, and collect like terms. 90 = b + 1.5b + 3 + 15 + 2b – 9

90 = 4.5b + 9

4 0

2 years ago

Find the area of this circle.

SashulF [63]

Answer:

not sure man... goodluck tho

3 0

2 years ago

Read 2 more answers

Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -

rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

$y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\$

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by D and its formula is

$D=b^2-4ac\\$

Where

a= the coefficient of the $x^{2}$

b= the coefficient of $x$

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant and evaluate our answer accordingly .

Let us start with

$y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\$

Hence we have two real roots for this equation.

$y = 2x^2 - 6x + 5\\$

$y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D$

Hence we do not have any real root for this quadratic

$y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\$

Hence D>0 and thus we have two real roots for this equation.

$y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\$

Hence we have one real root to this quadratic equation.

7 0

2 years ago

I need help with this problem​

I need help with this problem