1) Size of the image: 2 cm
In order to calculate the size of the image, we can use the following proportion:
![p:q = h_o : h_i](https://tex.z-dn.net/?f=p%3Aq%20%3D%20h_o%20%3A%20h_i)
where
p = 80 m is the distance of the tree from the pinhole
q = 20 cm = 0.2 m is the distance of the image from the pinhole
= 8 m is the heigth of the object
is the height of the image
By re-arranging the proportion, we find
![h_i = \frac{h_o \cdot q}{p}=\frac{(8 m)(0.2 m)}{80 m}=0.02 m=2 cm](https://tex.z-dn.net/?f=h_i%20%3D%20%5Cfrac%7Bh_o%20%5Ccdot%20q%7D%7Bp%7D%3D%5Cfrac%7B%288%20m%29%280.2%20m%29%7D%7B80%20m%7D%3D0.02%20m%3D2%20cm)
2) Magnification: 0.0025
The magnification of a camera is given by the ratio between the size of the image and the size of the real object:
![M=\frac{h_i}{h_o}](https://tex.z-dn.net/?f=M%3D%5Cfrac%7Bh_i%7D%7Bh_o%7D)
so, in this problem we have
![M=\frac{0.02 m}{8 m}=0.0025](https://tex.z-dn.net/?f=M%3D%5Cfrac%7B0.02%20m%7D%7B8%20m%7D%3D0.0025)
Look at the first person’s answer. Cause I know I’m wrong
Answer:
this is a difficult question but I will try to answer it answer for this is 3220 a + b b u s y d l new