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9966 [12]
2 years ago
10

How much force is required to accelerate a 12 kg mass at 5 m/s 2

Physics
1 answer:
Savatey [412]2 years ago
4 0

Answer:

60 N

Explanation:

This is just Newton's Second Law

F = m*a

F = ?

m = 12 kg

a = 5 m/^2

F = 5*12 = 60 Newtons

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Ben walks 500 meters from his house to the corner store. He then walks back toward his house but stops to talk to a neighbor whe
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Average velocity =

      (displacement) / (time for the displacement)
and
      (direction of the displacement) .

Displacement =

      (distance from the start-point to the end-point)
and
      (direction from the start-point to the end-point)   .

When Ben is 200 meters from the corner store,
he is (500 - 200) = 300 meters from his house.

His displacement is

         300 meters in the direction
                             from his house to the neighbor .


His average velocity is

         (300/910) =  0.33 meters per second, in the
                               direction from his house to the neighbor .


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3 years ago
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A 90.0 kg man climbs hand over hand up a rope to a height of 9.47 m. How much potential energy does he have at the top?
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Answer:

8361.063 J

Explanation:

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2 years ago
Type O blood is known as the universal donor why is this so?
bagirrra123 [75]
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Which phase occurs between the new moon and the first quarter?
Igoryamba

Answer:

<em>waxing gibbous moon</em>

<em>It comes a week after new moon. <u>A waxing gibbous moon</u> occurs when more than half of the lit portion of the Moon can be seen and the shape increases ("waxes") in size from one day to the next. The waxing gibbous phase occurs between the first quarter and full moon phases.</em>

4 0
3 years ago
A student on a tower 49 m height drops a stone. One second later he throws a second stone after the first. They both hit the gro
ohaa [14]

By applying the second equation of motion, the speed at which he threw the second stone is equal to 12.10 m/s.

<h3>How to determine the speed?</h3>

First of all, we would calculate the time taken by the first stone to reach a height of 49 meters by applying the second equation of motion as follows:

S = ut + ½gt²

49 = 0(t) + ½ × 9.8 × t²

49 = 4.9t²

t² = 49/4.9

t = √10

t = 3.16 seconds.

Now, we can determine the speed at which he threw the second stone:

<u>Note:</u> Time = 3.16 - 1 = 2.16 seconds.

S = ut + ½gt²

49 = u(2.16) + ½ × 9.8 × 2.16²

49 = 2.16u + 22.86

2.16u = 49 - 22.86

u = 26.14/2.16

u = 12.10 m/s.

Read more on initial speed here: brainly.com/question/19365526

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2 years ago
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