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Lena [83]
1 year ago
12

d. e. Study the given diagram and calculate the following: i. work done by load ii. work done by effort iii. M.A iv. V.R v. effi

ciency [Friction is neglected] ​

Physics
1 answer:
il63 [147K]1 year ago
4 0

i. The work done by the load is load x distance moved by load.

ii. The work done by effort is effort applied x distance moved by effort.

iii. The mechanical advantage of the simple machine is Load/effort.

iv. The velocity ratio of the simple machine is 2.

v. The efficiency of the machine is M.A/V.R x 100%.

<h3>Work done by the load</h3>

The work done by the load is the product of the load and the distance through which the load is moved. The magnitude is calculated as follows;

Work done by the load = load x distance moved by load

<h3>Work done by effort</h3>

The work done by the effort is the product of the effort and the distance through which the effort is applied. The magnitude is calculated as follows;

Work done by effort = effort applied x distance moved by effort

<h3>Mechanical advantage of the simple machine</h3>

M.A = Load/Effort

<h3>Velocity ratio of the simple machine</h3>

V.R = distance moved by effort / distance moved by load

V.R  = 30 cm/15 cm

V.R = 2

<h3>Efficiency of the machine</h3>

E = (M.A/V.R) x 100%

Thus, the work done by the load is load x distance moved by load.

The work done by effort is effort applied x distance moved by effort.

The mechanical advantage of the simple machine is Load/effort.

The velocity ratio of the simple machine is 2.

The efficiency of the machine is M.A/V.R x 100%.

Learn more about mechanical advantage here: brainly.com/question/25984831

#SPJ1

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