it would be species in this case
Answer:
T2 = 29°C
Explanation:
Given data:
Heat added = 420 j
Mass of water = 25 g
Initial temperature = 25°C
Final temperature = ?
Solution;
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Specific heat capacity of water = 4.18 j/g.°C
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values.
420 j = 25 g ×4.18 j/g.°C × (Final temperature - initial temperature)
420 j = 25 g ×4.18 j/g.°C × (T2 - 25°C)
420 j = 104.5 j/°C × (T2 - 25°C)
420 j /104.5 j/°C = T2 - 25°C
4°C + 25°C = T2
T2 = 29°C
Answer:
Properties of Liquids
Capillary Action. ...
Cohesive and Adhesive Forces. ...
Contact Angles. ...
Surface Tension. ...
Unusual Properties of Water. ...
Vapor Pressure. ...
Viscosity Viscosity is another type of bulk property defined as a liquid's resistance to flow. ...
Wetting Agents
Answer:
So, H2O means two atoms of hydrogen mixed with one atom of oxygen. All pure water is the same, two parts hydrogen to one part oxygen. ... Water cannot be separated by any physical means.
Explanation:
Logic and my notes from chem....
Correct Answer: option C:The pair which consist of molecules having the same geometry is CH2CCI2 and CH2CH2.
Reason:
Both of the above molecules contain double bonds. They are characterized by sp^2 hybridization. Also, they possess a trigonal planar geometry. In trigonal planar system, the molecule consist of three equally spaced sp^2 hybrid orbitals, which arranged at angle 120 degree.
