Carbon -14 and Carbon 12 are the two substances geologists use in radiocarbon dating.
Answer: Option B
<u>Explanation:
</u>
Radiocarbon dating denotes the determination process of the age of fossils of plants or animals based on the ratio of carbon atoms 14 to 12. Carbon naturally exists in two non-radioactive isotopes, Carbon-12 and Carbon-13 and one radioactive isotope carbon 14. The carbon 14 gets released on continuous cosmic reaction with atmospheric nitrogen.
These carbon 14 will be absorbed by the living plants and from the plants. Then, it will enter inside the animals which consume the plants. But once the plants and animals died, they ceased to intake carbon-14. In their living state, the ratios of carbon atoms 14 to 12 in them tends to similar to the ratio in atmosphere.
But after they die, the ratio of C-14 to C-12 will be varying from the ratio of C-14 to C-12 in atmosphere as the concentration of C-14 will be decreasing in the dead animals and plants. Thus using this ratio, geologists can find the fossil's age.
Answer:
Iron shavings
Explanation:
A substance that has a fixed chemical composition throughout and a mixture is when two or more substances are combined, but they are not combined chemically.
Technically speaking, yes you can. Using a microscope though.
The question is incomplete, here is the complete question:
Carbon tetrachloride reacts at high temperatures with oxygen to produce two toxic gases, phosgene and chlorine.
at 1,000 K
Calculate Kc for the reaction ![2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)](https://tex.z-dn.net/?f=2CCl_4%28g%29%2BO_2%28g%29%5Crightleftharpoons%202COCl_2%28g%29%2B2Cl_2%28g%29)
<u>Answer:</u> The value of
for the final reaction is ![1.936\times 10^{19}](https://tex.z-dn.net/?f=1.936%5Ctimes%2010%5E%7B19%7D)
<u>Explanation:</u>
The given chemical equations follows:
![CCl_4(g)+\frac{1}{2}O_2(g)\rightleftharpoons COCl_2(g)+Cl_2(g);K_c](https://tex.z-dn.net/?f=CCl_4%28g%29%2B%5Cfrac%7B1%7D%7B2%7DO_2%28g%29%5Crightleftharpoons%20COCl_2%28g%29%2BCl_2%28g%29%3BK_c)
We need to calculate the equilibrium constant for the equation, which is:
![2CCl_4(g)+O_2(g)\rightleftharpoons 2COCl_2(g)+2Cl_2(g)](https://tex.z-dn.net/?f=2CCl_4%28g%29%2BO_2%28g%29%5Crightleftharpoons%202COCl_2%28g%29%2B2Cl_2%28g%29)
As, the final reaction is the twice of the initial equation. So, the equilibrium constant for the final reaction will be the square of the initial equilibrium constant.
The value of equilibrium constant for net reaction is:
![K_c'=(K_c)^2](https://tex.z-dn.net/?f=K_c%27%3D%28K_c%29%5E2)
We are given:
![K_c=4.4\times 10^9](https://tex.z-dn.net/?f=K_c%3D4.4%5Ctimes%2010%5E9)
Putting values in above equation, we get:
![K_c'=(4.4\times 10^9)^2=1.936\times 10^{19}](https://tex.z-dn.net/?f=K_c%27%3D%284.4%5Ctimes%2010%5E9%29%5E2%3D1.936%5Ctimes%2010%5E%7B19%7D)
Hence, the value of
for the final reaction is ![1.936\times 10^{19}](https://tex.z-dn.net/?f=1.936%5Ctimes%2010%5E%7B19%7D)