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3 years ago

While rowing across a lake, John does 3960 ft-lbs of work over 120 ft. How much force is John using?

1 answer:

6 0

66W. Explanation: Formula of Power: Worktimetaken. Given: Work = 3960J and time taken = 60.0s. Using the formula: Worktimetaken. = 3960J60.0s. = 66W.

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10. What does a profile of a river from its headwaters to its mouth typically show?

irina1246 [14]

Answer:

c. an abrupt increase followed by a gradual decrease

Explanation:

At the headwater, the flow gradient starts high but then slowly decreases as the river moves downstream to its mouth.

3 0

3 years ago

No question but thx reeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

jeka94

Answer:

why you doin this

Explanation:

is this so we get free points?

5 0

3 years ago

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The angle of twist can be computed using the material’s shear modulus if and only if: (a)- The shear stress is still in the elas

ollegr [7]

Answer:

The angle of twist can be computed using the material’s shear modulus if and only if the shear stress is still in the elastic region

Explanation:

The shear modulus (G) is the ratio of shear stress to shear strain. Like the modulus of elasticity, the shear modulus is governed by Hooke’s Law: the relationship between shear stress and shear strain is proportional up to the proportional limit of the material. The angle of twist can be computed using the material’s shear modulus if and only if the shear stress is still in the elastic region.

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4 years ago

A 100 ft long steel wire has a cross-sectional area of 0.0144 in.2. When a force of 270 lb is applied to the wire, its length in

blondinia [14]

Answer:

(a) The stress on the steel wire is 19,000 Psi

(b) The strain on the steel wire is 0.00063

Explanation:

Given;

length of steel wire, L = 100 ft

cross-sectional area, A = 0.0144 in²

applied force, F = 270 lb

extension of the wire, e = 0.75 in

Part (A) The stress on the steel wire;

δ = F/A

= 270 / 0.0144

δ = 18750 lb/in² = 19,000 Psi

Part (B) The strain on the steel wire;

σ = e/ L

L = 100 ft = 1200 in

σ = 0.75 / 1200

σ = 0.00063

Part (C) The modulus of elasticity of the steel

E = δ/σ

= 19,000 / 0.00063

E = 30,000,000 Psi

4 0

3 years ago

Write a program that removes all spaces from the given input. You may assume that the input string will not exceed 50 characters

GrogVix [38]

Answer:

Program that removes all spaces from the given input

Explanation:

// An efficient Java program to remove all spaces

// from a string

class GFG

{

// Function to remove all spaces

// from a given string

static int removeSpaces(char []str)

{

// To keep track of non-space character count

int count = 0;

// Traverse the given string.

// If current character

// is not space, then place

// it at index 'count++'

for (int i = 0; i<str.length; i++)

if (str[i] != ' ')

str[count++] = str[i]; // here count is

// incremented

return count;

}

// Driver code

public static void main(String[] args)

{

char str[] = "g eeks for ge eeks ".toCharArray();

int i = removeSpaces(str);

System.out.println(String.valueOf(str).subSequence(0, i));

}

5 0

4 years ago

Read 2 more answers