Answer:
the minimum shaft diameter is 35.026 mm
the maximum shaft diameter is 35.042mm
Explanation:
Given data;
D-maximum = 35.020mm and d-minimum = 35.000mm
we have to go through Tables "Descriptions of preferred Fits using the Basic Hole System" so from the table, locational interference fits H7/p6
so From table, Selection of International Trade Grades metric series
the grade tolerance are;
ΔD = IT7(0.025 mm)
Δd = IT6(0.016 mm)
Also from Table "Fundamental Deviations for Shafts" metric series
Sf = 0.026
so
D-maximum
Dmax = d + Sf + Δd
we substitute
Dmax = 35 + 0.026 + 0.016
Dmax = 35.042 mm
therefore the maximum diameter of shaft is 35.042mm
d-minimum
Dmin = d + Sf
Dmin = 35 + 0.026
Dmin = 35.026 mm
therefore the minimum diameter of shaft is 35.026 mm
Answer:
IDK
Explanation:
same thing is happening to me
The three most common software development methods are the Waterfall Approach, the Incremental Approach, and the SPIRAL Approach. These methods depend on the team size and specific goals.
Software development is the sequential procedure that involves the division of the work into smaller and parallel stages in order to improve software design and product management.
The software development methods depend on both the team size and specific objectives.
The most common methodologies for software development include:
- Waterfall
- Spiral
- Incremental
- Agile
- Continuous integration
Learn more about software development here:
brainly.com/question/14275830
Answer:
<em>T = 25.41 Nm</em>
Explanation:
Calculating Nsync (Synchronous Speed):
Calculating s (Slip):
![s = (Nsync - Nm) / Nsync \\[tex]s = (3600-2464)/3600\\s = 0.3156](https://tex.z-dn.net/?f=s%20%3D%20%28Nsync%20-%20Nm%29%20%2F%20Nsync%20%5C%5C%3C%2Fp%3E%3Cp%3E%5Btex%5Ds%20%3D%20%283600-2464%29%2F3600%5C%5Cs%20%3D%200.3156)
Calculating Vth (Thevenin Voltage):
Calculating Rth (Thevenin Resistance):
Calculating Xth (Thevenin Reactance):
Xth = Xs = 1.3 ohm
Calculating Torque:
![T = (3Vth^{2}Rr/s) / (Wsync[(Rth+Rr/s)^{2} + (Xth + Xr)^{2}])\\T = (3*205.39*0.7/0.3156) / 377[(2.22+0.7/0.315)^{2} + (1.3+1.8)^{2}]](https://tex.z-dn.net/?f=T%20%3D%20%283Vth%5E%7B2%7DRr%2Fs%29%20%2F%20%28Wsync%5B%28Rth%2BRr%2Fs%29%5E%7B2%7D%20%2B%20%28Xth%20%2B%20Xr%29%5E%7B2%7D%5D%29%5C%5CT%20%3D%20%283%2A205.39%2A0.7%2F0.3156%29%20%2F%20377%5B%282.22%2B0.7%2F0.315%29%5E%7B2%7D%20%2B%20%281.3%2B1.8%29%5E%7B2%7D%5D)
T = 280699 / 377 [19.69 + 9.61]
<em>T = 25.41 Nm</em>
Answer:
cout<<"''<<user_word<<"' "<<user_number;
Explanation:
The above question was answered using C++ programming language.
The keyword cout represents print and it carries out print operation only.
It prints all variable in front of it.
Assume the values of user_word and user_number to be Charles and 20, respectively.
The output of the above instruction would be
'Charles' 20 just as it is in the sample output in the question.
In java programming language, it is
System.out.print("'"+user_word+"' "+user_number);
In Qbasic, it is
PRINT "'"+user_word+"' "+ user_number
