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egoroff_w [7]
2 years ago
11

PLEASE HELP!! ill give you 20 points ​

Mathematics
1 answer:
const2013 [10]2 years ago
7 0

Step-by-step explanation:

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Triangle DEF, with vertices D(2, 5), E(6, 4), and F(3, 3), is reflected across the line y=x. A student determined one of the ver
4vir4ik [10]
The vertices of the image reflected over the line y = x are:
D´( 5 , 2 ),  E´( 4, 6 ) and F´( 3, 3 ).
So ( 2, -5 ) is incorrect and it could be incorrectly reflected across over the x-axis.
Answer: B) 
4 0
3 years ago
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Quadrant:
NISA [10]

<h2>✒️Area Between Curves</h2>

\small\begin{array}{ |c|c} \hline \bold{Area\ Between\ Curves} \\ \\ \textsf{Solving for the intersection of }\rm y = x^2 + 2\textsf{ and }\\ \rm y = 4, \\ \\ \qquad \begin{aligned} \rm y_1 &=\rm y_2 \\ \rm x^2 + 2 &=\rm 4 \\ \rm x^2 &= \rm 2 \\ \rm x &=\rm \pm \sqrt{2} \end{aligned} \\ \\ \textsf{We only need the first quadrant area bounded} \\ \textsf{by the given curves so the integral for the area} \\ \textsf{would then be} \\ \\ \boldsymbol{\displaystyle \rm A = \int_{\ a}^{\ b} {\left( \begin{array}{c}\text{upper} \\ \text{function}\end{array} \right) - \left( \begin{array}{c} \text{lower} \\ \text{function} \end{array} \right)\ dx}} \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} \Big[4 - (x^2 + 2)\Big]\ dx \\ \\ \displaystyle \rm A = \int_{0}^{\sqrt{2}} (2 - x^2)\ dx \\ \\ \rm A = \left[2x - \dfrac{x^3}{3}\right]_{0}^{\sqrt{2}} \\ \\ \rm A = 2\sqrt{2} - \dfrac{\big(\sqrt{2}\big)^3}{3} \\ \\ \rm A = 2\sqrt{2} - \dfrac{2\sqrt{2}}{3} \\ \\\red{\boxed{\begin{array}{c} \rm A = \dfrac{4\sqrt{2}}{3}\textsf{ sq. units} \\ \textsf{or} \\ \rm A \approx 1.8856\textsf{ sq. units} \end{array}}} \\\\\hline\end{array}

#CarryOnLearning

#BrainlyForTrees

\qquad\qquad\qquad\qquad\qquad\qquad\tt{Monday\:at \: 04-04-2022} \\ \qquad\qquad\qquad\qquad\qquad\qquad\tt{12:10 \: pm}

5 0
2 years ago
Find the percent of decrease from 87 pounds to 16 pounds. Round to the nearest tenth of a percent if necessary. Should be in per
irina1246 [14]

Answer:

81.6

Step-by-step explanation:

7 0
2 years ago
For U.S. adult males, the mean height is 174 cm with a standard deviation of 5 cm and the mean weight is 86 kg with a standard d
Genrish500 [490]

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The answer is

Height and weight have the same degree of variation

3 0
2 years ago
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S(t)=9t-4, find S(4)
melamori03 [73]
For this problem, you need to substitute 4 in for your variable t. the original equation is S(t) and the one you need is S(4) -- in other words, evaluate this equation when t = 4.

S(4) = 9(4) - 4
S(4) = 36 - 4
S(4) = 32 is your answer.
3 0
3 years ago
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