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Oxana [17]
3 years ago
5

Solid mercury (II) oxide produces liquid mercury and oxygen gas

Chemistry
1 answer:
Nina [5.8K]3 years ago
7 0

Mercury(II) oxide, a red solid, decomposes when heated to produce mercury and oxygen gas. Mercury(II) oxide is a red solid. When it is heated, it decomposes into mercury metal and oxygen gas. A reaction is also considered to be a decomposition reaction even when one or more of the products are still compounds.

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Please help me!!!!!!
Norma-Jean [14]

Answer:

17.8ml-15.6ml is 2.2 ml then convert to cm so 2.2cm^3

4 0
2 years ago
Why does aluminium oxide (Al2O3) have a higher melting point than sodium oxide (Na2O)?
Lilit [14]

Al2O3 has a higher melting point than Na2O. This is because the ionic bond between Al3+ ions and O2- ions is stronger than that between Na+ and O2-. The charge on the Al3+ ion is larger than that of the Na+ ion

5 0
3 years ago
In an chemicalbreaction involving Fe and S, it was found that 45.2 g of Fes was produced. If the percent yield of the reaction i
saw5 [17]

Answer:

47.8 g

Explanation:

Remember the equation for percent yield:

% yield = actual / theoretical

We're given two of the values in the question, so plug n' play:

0.945 = 45.2 / theoretical

theoretical = 47.8 g

Keep in mind you can use mass here without converting to moles because we're working with products only. If you were given a mass of reactants, you would need to convert to moles and using a balanced chemical equation find the corresponding moles of product produced.

7 0
3 years ago
What is another name for the representative elements?
jeka94

Answer:

Group A elements or the main group

Another name for the representative elements are  the Group A elements or the main group elements

Explanation:

6 0
3 years ago
Read 2 more answers
For a molecule of fluorous acid, the atoms are arranged as HOFO. (Note: In this oxyacid, the placement of fluorine is an excepti
Maksim231197 [3]

Answer:

0,0,0,0

Explanation:

The formal charge formula:

Formal charge= Valence electrons - lone pair electrons - 0.5 shared electrons

So:

Hydrogen: 1 elec. of valence and shares two electrons with the O

Formal charge= 1 - 0 - 0.5*2=0

Oxygen: 6 elec. of valence, 2 lone pairs and shares two electrons with the H and two with the F

Formal charge= 6 - 4 - 0.5*4=0

Fluorine: 7 elec. of valence, 6 lone pairs and shares two electrons with the O

Formal charge= 7 - 6 - 0.5*2=0

Oxygen: 6 elec. of valence, 3 lone pairs

Formal charge= 6 - 6 - 0.5*0=0

Note: the dative bond between F and the second O doesn't count as shared electrons.

8 0
3 years ago
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