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Evgesh-ka [11]
3 years ago
5

Does rapid burial increase exposure to oxygen?

Chemistry
1 answer:
vovangra [49]3 years ago
7 0

Answer:

yes but very little exposure

Explanation:

a gentle burial also increases an organisms chances of becoming more fossil like

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Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits<br> and put the units.
marta [7]

Answer:

Approximately 53.3\; \rm g.

Explanation:

Lookup Avogadro's Number: N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1} (three significant figures.)

Lookup the relative atomic mass of \rm H, \rm S, and \rm O on a modern periodic table:

  • \rm H: 1.008.
  • \rm S: 32.06.
  • \rm O: 15.999.

(For example, the relative atomic mass of \rm H is 1.008 means that the mass of one mole of \rm H\! atoms would be approximately 1.008\! grams on average.)

The question counted the number of \rm H_2SO_4 molecules without using any unit. Avogadro's Number N_{\rm A} helps convert the unit of that count to moles.

Each mole of \rm H_2SO_4 molecules includes exactly (1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23} of these \rm H_2SO_4 \! molecules.

3.27 \times 10^{23} \rm H_2SO_4 molecules would correspond to \displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of \rm H_2SO_4 gives the mass of each mole of \rm H_2SO_4\! molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}.

Calculate the mass of approximately 0.541389\; \rm mol of \rm H_2SO_4:

\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}.

(Rounded to three significant figures.)

6 0
3 years ago
Which functional group does the molecule below contain
DedPeter [7]

Answer:

All functional groups in organic chemistry

Functional groups include: hydroxyl, methyl, carbonyl, carboxyl, amino, phosphate, and sulfhydryl.

Hope this helps Have a good day

7 0
3 years ago
Read 2 more answers
Your teacher needs a 3.0M solution acid, but only has a 12.0M stock solution of sulfuric acid in the chemical store room. Calcul
arlik [135]

Answer:

The calculations are in the explanation below.

The <em>steps </em>are:

  • 1. Using a graduated pipette, accurately take 25mL of the 12.0M stock solution.
  • 2. Pour the 25mL of stock solution into a 100 mL volumetric flask
  • 3. Add distilled water up to the mark
  • 4. Cap the flask with the stopper
  • 5. Stirr by gently rotating the flask.

Explanation:

To make 100 mililiter of the 3.0M solution of sulfuric acid, first you must calculate the volume of the 12.0M stock solution that contains the same number of moles as the diluted solution.

For that, you use the dilution formula:

  • number of moles = C₁V₁ = C₂V2
  • 12.0M×V₁ = 3.0M × 100mL
  • V₁ = 3.0M × 100mL/12.0M = 25mL

Then, the steps are:

1. Using a graduated pipette, accurately take 25mL of the 12.0M stock solution.

2. Pour the 25mL of stock solution into a 100 mL volumetric flask

3. Add distilled water up to the mark

4. Cap the flask with the stopper

5. Stirr by gently rotating the flask.

3 0
3 years ago
A scientist makes several observations, develops a question, researches what is known about the question, forms a hypothesis, an
Alex73 [517]
The scientist should make a new hypothesis and do a new experiment! That is what I say!
8 0
3 years ago
How many moles of HCl are required to neutralize all 0.050 mol of Ca(OH)2
Andrew [12]
3......................................
8 0
3 years ago
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