Gina surveyed students about their lunch time preference. Out of 50 students, 20 prefer eating lunch at 11:00am, 15 prefer eating at 11:15a.m., 10 prefer eating at 11:30a.m. , and 5 have no preference. Based on the information, what is the probability that a student chosen at random has no lunch time preference?
Btw I got this answer from gauth math
answer: 2x -3
Explanation
Solution: Move the straight line and its slope, remains unchanged, and y-axis focus change
First point (0,1)
x=0, -3*0+2y=2, y=1
second point (2,4)
-3x+2y=2
x=2, -3*2+2y=2, -6+2y=2, 2y=8, y=4
third point (-2, -2)
x=-2, -3*(-2)+2y=2, 6+2y=2, 2y=-4, y=-2
Answer:
The slope is 3/4
Step-by-step explanation:
Answer:27/220
Step-by-step explanation:
She must have 2 �1 coins and 1 50p coin.
She can choose the 2 �1 coins 3C2 = 3 ways.
For each of those 3 ways she can choose the
50p coin 9C1 or 9 ways.
That's 3�9=27 ways to get �2.50.
She can choose any 3 coins in 12C3 = 220 ways.
The desired probability is 27 ways out of
220 ways,or 27/220, or 13.5% of the time.
