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sp2606 [1]
3 years ago
15

Type of force that holds the nucleus of an atom together

Physics
1 answer:
Kamila [148]3 years ago
7 0

Answer:

Nuclear Forces

Explanation:

The type  of force that holds the nucleus of an atom together is called Nuclear Forces.

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A 30kg boxed is pushed with a force of 20N. What is the boxes acceleration. Please show work
kozerog [31]

Answer:

<h3>The answer is 0.67 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{20}{30}  =  \frac{2}{3}  \\  = 0.6666666...

We have the final answer as

<h3>0.67 m/s²</h3>

Hope this helps you

8 0
3 years ago
A gas has a volume of 6 L, a temperature of 70 degrees C, and a pressure of 2 atm. If the gas is compressed to a volume of 4 L,
Lelu [443]
I would say check the back of the book
4 0
3 years ago
This is a change in an object's position. <br> Net Force<br> Gravitational Pull<br> Motion<br> Force
alexira [117]

Answer:

Motion

Explanation:

because when something moves its call motion

3 0
3 years ago
8. Fig. 4.1 shows a heavy ball B of weight W suspended from a fixed beam by two ropes P and Q.
mart [117]

Answer:

The resultant tension of the two ropes is approximately 42.4 N

The length of the line representing the resultant tension is approximately 8.48 cm

Please find included  with the answer the scale drawing created with Microsoft Word

Explanation:

The given parameters are;

The tension in rope P, T_P = 30 N

The tension in rope Q, T_Q = 30 N

The angle the rope, 'P', makes with the horizontal = 45°

The angle the rope, 'Q', makes with the horizontal = 45°

The scale factor of the scale diagram, S.F. = 5.0 N/cm

By the resolution of forces at equilibrium, we have;

The sum of the vertical forces, \Sigma F_y = T_P_y + T_Q_y + W = 0

∴ W = -(T_P_y + T_Q_y)

W = -(30 × sin(45°) + 30 × sin(45°)) = -42.4264068712

The weight of the heavy ball, W ≈ 42.4 N acting downwards

The sum of the horizontal forces, \Sigma F_x = T_P_x + T_Q_x  = 0

The length of the resultant force, W = W/(S.F.) ≈ 42.4 N/(5.0 N/cm) = 8.48 cm

The drawing of the vectors using the scale factor of 5.0 N/cm is created using Microsoft Word is included

3 0
2 years ago
The average distance an electron travels between collisions is 2.0 μmμm . What acceleration must an electron have to gain 2.0×10
Ilya [14]

The solution is in the attachment

4 0
2 years ago
Read 2 more answers
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