1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sp2606 [1]
3 years ago
15

Type of force that holds the nucleus of an atom together

Physics
1 answer:
Kamila [148]3 years ago
7 0

Answer:

Nuclear Forces

Explanation:

The type  of force that holds the nucleus of an atom together is called Nuclear Forces.

You might be interested in
ANSWER ASAPPPPPPPP BE 100% CORRECT
AfilCa [17]
Mass of a sample of gas doesn't change, no matter what happens to its pressure, volume, or temperature.
7 0
3 years ago
Find the sum 5.24 g, 43.261 g, and 7.3458 g. Write your answer with the correct amount of significant figures.
lapo4ka [179]

Answer:

This is how I do it:

  • 5.24 rounded to one significant figure is 5
  • 43.261 rounded to one significant figure is 40.
  • 7.3458 rounded to one significant figure is 7.
  • 5 + 40 + 7 is 52 g

Hope this helps you.

Explanation:

7 0
3 years ago
A child is sliding down a slide at the playground. is the mechanical energy conserved. why or why not.
aleksandrvk [35]
C: the mechanical energy isn't conserved. Some energy was lost to friction. 
6 0
2 years ago
Read 2 more answers
6) Find the speed a spherical raindrop would attain by falling from 4.00 km. Do this:a) In the absence of air dragb) In the pres
sleet_krkn [62]

We are asked to determine the velocity of a rain drop if it falls from 4 km.

To do that we will use the following formula:

2ah=v_f^2-v_0^2

Where:

\begin{gathered} a=\text{ acceleration} \\ h=\text{ height} \\ v_f,v_0=\text{ final and initial velocity} \end{gathered}

If we assume the initial velocity to be 0 we get:

2ah=v_f^2

The acceleration is the acceleration due to gravity:

2gh=v_f^2

Now, we take the square root to both sides:

\sqrt{2gh}=v_f

Now, we substitute the values:

\sqrt{2(9.8\frac{m}{s^2})(4000m)}=v_f

solving the operations:

280\frac{m}{s}=v

Therefore, the velocity without air drag is 280 m/s.

Part B. we are asked to determine the velocity if there is air drag. To do that we will use the following formula:

F_d=\frac{1}{2}C\rho_{air}Av^2

Where:

\begin{gathered} F_d=drag\text{ force} \\ C=\text{ constant} \\ \rho_{air}=\text{ density of air} \\ A=\text{ area} \\ v=\text{ velocity} \end{gathered}

We need to determine the drag force. To do that we will use the following free-body diagram:

Since the velocity that the raindrop reaches is the terminal velocity and its a constant velocity this means that the acceleration is zero and therefore the forces are balanced:

F_d=mg

Now, we determine the mass of the raindrop using the following formula:

m=\rho_{water}V

Where:

\begin{gathered} \rho_{water}=\text{ density of water} \\ V=\text{ volume} \end{gathered}

The volume is the volume of a sphere, therefore:

m=\rho_{water}(\frac{4}{3}\pi r^3)

Since the diameter of the raindrop is 3 millimeters, the radius is 1.5 mm or 0.0015 meters. Substituting we get:

m=(0.98\times10^3\frac{kg}{m^3})(\frac{4}{3}\pi(0.0015m)^3)

Solving the operations:

m=1.39\times10^{-5}kg

Now, we substitute the values in the formula for the drag force:

F_d=(1.39\times10^{-5}kg)(9.8\frac{m}{s^2})

Solving the operations:

F_d=1.36\times10^{-4}N

Now, we substitute in the formula:

1.36\times10^{-4}N=\frac{1}{2}C\rho_{air}Av^2

Now, we solve for the velocity:

\frac{1.36\times10^{-4}N}{\frac{1}{2}C\rho_{air}A}=v^2

Now, we substitute the values. We will use the area of a circle:

\frac{1.36\times10^{-4}N}{\frac{1}{2}(0.45)(1.21\frac{kg}{m^3})(\pi r^2)}=v^2

Substituting the radius:

\frac{1.36\cdot10^{-4}N}{\frac{1}{2}(0.45)(1.21\frac{kg}{m^{3}})(\pi(0.0015m)^2)}=v^2

Solving the operations:

70.67\frac{m^2}{s^2}=v^2

Now, we take the square root to both sides:

\begin{gathered} \sqrt{70.67\frac{m^2}{s^2}}=v \\  \\ 8.4\frac{m}{s}=v \\  \end{gathered}

Therefore, the velocity is 8.4 m/s

7 0
1 year ago
According to the definition of mechanical work, pushing on a rock accomplishes no work unless there is
LekaFEV [45]
There must be movement in the same direction as the force put on the object. Hope this helps!
4 0
3 years ago
Read 2 more answers
Other questions:
  • Water flows at speed v in a pipe of radius R. At what speed does the water flow through a constriction in which the radius of th
    10·1 answer
  • The kinetic energy of a proton and that of an a-particle are 4 eV and 1 eV,
    15·1 answer
  • How far away is the sun?
    5·1 answer
  • Thinking about the winter we missed out on this year. Calvin and his tiger go sledding down a snowy hill. There is friction betw
    9·1 answer
  • Exercise 15.1 (a) Find the magnitude of the electric force between two protons separated by 1 femtometer (10^-15), approximately
    15·1 answer
  • Nodes give a vertebrate’s back flexibility.<br> A. True<br> B. False
    7·2 answers
  • Anne should use a to transfer electric energy into motion. She should also use a to start and stop the flow of current.
    15·1 answer
  • A truck, initially at rest, rolls down a frictionless hill and attains a speed of 20 m/s at the bottom. To achieve a speed of 40
    10·1 answer
  • Nighttime is the result of
    15·2 answers
  • Why do protons and neutrons need to be the same
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!