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3 years ago

Whats the height and temp for tropopause

1 answer:

8 0

The height for the tropopause is the tropopause is about 20 km (12 miles or 65,000 feet) above sea level. It's temperature typically, drops about 6.5° C with each increase in altitude of 1 kilometer (about 3.6° F per 1,000 feet).

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D. All of the above.

Explanation:

PV=nRT

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3 years ago

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4 years ago

A gasoline engine transform approximately 34 percent of the fuel's chemical energy into mechanical energy. if energy is conserve

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3 years ago

A ski gondola is connected to the top of a hill by a steel cable oflength 620 m and diameter 1.5 cm. As thegondola comes to the

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Answer:

Explanation:

Given

Length of cable $L=620 m$

Diameter of cable $d=1.5 cm$

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time taken to cover distance L

$t=\frac{T}{2}=7 s$

velocity

$v=\frac{L}{t}=\frac{620}{7}=88.57 m/s$

(b)Relation between velocity of wave Tension is

$v=\sqrt{\frac{T}{\mu }} , where \mu =$ mass per unit Length

$T=v^2\cdot \mu$

$T=(88.57)^2\cdot \frac{m}{L}$

$T=(88.57)^2\cdot \frac{\rho AL}{L}$

where $\rho =density\ of\ steel =7850 kg/m^3$

$A=area\ of\ cross-section=\frac{\pi }{4}d^2=1.76\times 10^{-4} cm^2$

$T=(88.57)^2\cdot 7850\times 1.76\times 10^{-4}$

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3 years ago

A constant-volume perfect gas thermometer indicates a pressure of 6.69 kPa at the triple point temperature of water (273.16 K).

mina [271]

Answer:

(a) ΔP=0.0245 kPa

(b) P=9.14 kPa

(c)ΔP=0.0245 kPa

Explanation:

(a) As it is perfect gas we can use

(P₁V₁)/T₁=(P₂V₂)/T₂

Since this constant volume so

P₁/T₁=P₂/T₂

T₂ is change in temperature

T₂=1.00+273.16

T₂=274.16 K

$P_{2}=(\frac{6.69}{273.16} )*274.16\\P_{2}=6.71449 kPa$

ΔP=6.71449-6.69

ΔP=0.0245 kPa

(b) As

$P_{2}=(\frac{6.69}{273.16} )*373.16\\P_{2}=9.14 kPa$

(c) Same steps as in part (a)

$P_{2}=(\frac{9.14}{373.16} )*374.16\\P_{2}=9.164kPa$

ΔP=9.164-9.14

ΔP=0.0245kPa

8 0

4 years ago

Whats the height and temp for tropopause​

Whats the height and temp for tropopause