Answer:
u go to vanguard? in 6th grade
The answer is <span>thermoplastics
hope this helps
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The final temperature of the mixture is closest to 32.5 °C
<h3>Data obtained from the question</h3>
- Mass of warm water (Mᵥᵥ) = 50 g
- Temperature warm water (Tᵥᵥ) = 40 °C
- Mass of cold water (M꜀) = 30 g
- Temperature of cold water (T꜀) = 20 °C
- Specific heat capacity of the water = 4.184 J/gºC
- Equilibrium temperature (Tₑ) =?
<h3>How to determine the equilibrium temperature </h3>
Heat loss = Heat gain
MᵥᵥC(Tᵥᵥ – Tₑ) = M꜀C(Tₑ – M꜀)
50 × 4.184 (40 – Tₑ) = 30 × 4.184(Tₑ – 20)
209.2(40 – Tₑ) = 125.52(Tₑ – 20)
Clear bracket
8368 – 209.2Tₑ = 125.52Tₑ – 2510.4
Collect like terms
8368 + 2510.4 = 125.52Tₑ + 209.2Tₑ
10878.4 = 334.72Tₑ
Divide both side by 334.72
Tₑ = 10878.4 / 334.72
Tₑ = 32.5 °C
Learn more about heat transfer:
brainly.com/question/6363778
The maximum mass of a load that can be lifted by the jack and the distance covered are:
m = 160.2 Kg
h = 25 cm
Given that a certain hydraulic jack is used for lifting load. a force of 250N is applied on a small piston with a diameter of 80cm while the diameter of the larger piston is 2.0m.
The parameters given are
= 250
= Area of the small piston = π
= 22/7 x 
= 0.5 
= ?
= Area of the large piston = π
= π x 1
= 3.14 
To calculate the force on the large piston, we will use the below formula
/
=
/ 
Substitute all the parameters into the equation
250/0.5 =
/3.14
= 1570 N
To calculate the maximum mass of a load that can be lifted by the jack, let us apply Newton second law
F = mg
1570 = 9.8m
m = 1570/9.8
m = 160.2 Kg
.(take g=9.81ms^-2)
If the applied force moves through a distance of 25cm, the distance through which the load is lifted will be
/ 0.25
=
/
h
250/0.125 = 1570/3.14h
make h the subject of the formula
6280h = 1570
h = 1570/6280
h = 0.25 m
Therefore, the distance through which the load is lifted is 25 cm
Learn more here: brainly.com/question/13596980
Answer:
Gravity
Explanation:
Pretty self-explanatory
We are kept on earth because of gravity and it keeps planets orbiting around the sun.