<h2>
Answer:D</h2>
Explanation:
Option A:
Surface waves are neither transverse nor longitudinal.They traverse perpendicularly or parallel to the wave's motion along the interface between different media.
Option B:
Transverse waves vibrate perpendicularly to the direction of the propagation of the wave.
Option C:
Sound is a longitudinal wave.Not a transverse wave.
Option D:
Transverse waves don't require a medium for propagation.But they propagate in medium too.
K.E = 1/2*m*v^2 = 1/2(500)(3)^2 = 2250 J
m*g*h = 500(9.8)(30) = 147000 J
2250 + 147000 = 149250
Answer:
<em>Magnitude of the Frictional force is 200 N</em>
Explanation:
The frictional force is the force that tries to oppose relative motion between two surfaces that are contacting. The coefficient of static friction is the coefficient of friction of a body that is not moving.
Newton's third law of motion states that action and reaction forces are equal and opposite. So the frictional force felt on the filing cabinet will be equal to the applied force pulling the cabinet.
Frictional force = Force applied
Force applied = 200 N
Therefore, the magnitude of the friction force on the filing cabinet is 200 N
Answer:
, charges are both positive or both negative
Explanation:
The electrostatic force between the two spheres is given by

where
k is the Coulomb's constant
q1 and q2 are the charges on the two spheres
r is the distance between the centres of the two spheres
In this problem, we have
is the force
is the distance between the spheres
because the two spheres have identical charge
Solving the formula for q, we find

And the two charges have the same sign (so, both positive or both negative), since the sign of the force is positive (+0.30 N), so it is a repulsive force.
The transfer of thermal energy as heat requires a difference in temperature between the two points of transfer. Heat may be transferred by means of conduction, convection, or radiation. Conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object.