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3 years ago

Rest and motion are relative terms. write in brief

Physics

1 answer:

Greeley [361]3 years ago

5 0

Answer:

Rest and motion are the relative terms because they depend on the observer's frame of reference. So if two different observers are not at rest with respect to each other, then they too get different results when they observe the motion or rest of a body.

Explanation With Example:

Imagine you are sitting inside a moving bus. When you look outside you will observe that you are moving. ... With respect to the roof of bus, you are at rest. Hence it is concluded that rest and motion are relative terms.

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Answer:

1. Work Is a type of Physical Activity

2. Power is Basically Having control of Society

Explanation:

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3 years ago

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What is the Milgram experiment?

lora16 [44]

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3 years ago

A speaker at the front of a room and an identical speaker at the rear of the room are being driven at 456 Hz by the same sound s

vampirchik [111]

Answer:

2.97795 Hz

Explanation:

v = Speed of sound in air = 343 m/s

$v_r$ = Relative speed between the speakers and the student = 1.12 m/s

$f'$ = Actual frequency of sound = 456 Hz

Frequency of sound heard as the student moves away from one speaker

$f_1=f'\dfrac{v-v_r}{v}\\\Rightarrow f_1=456\dfrac{343-1.12}{343}\\\Rightarrow f_1=454.51102\ Hz$

Frequency of sound heard as the student moves closer to the other speaker

$f_2=f'\dfrac{v+v_r}{v}\\\Rightarrow f_2=456\dfrac{343+1.12}{343}\\\Rightarrow f_2=457.48897\ Hz$

The difference in the frequencies is

$f_2-f_1=457.48897-454.51102=2.97795\ Hz$

The student hears 2.97795 Hz

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3 years ago

Which statement is the best explanation for the graph? (1 point)

sammy [17]

Answer:

zgzzhzhhzhxhxushd

hsus

Explanation:

jzhbzh hzgz

3 0

3 years ago

A pickup truck, initially stationary at a stop light, accelerates at a rate of 1.60m/s2 for 14.0 s. The truck then cruises at co

Alex Ar [27]

Answer:

The total distance traveled by the truck is 1797 m

Explanation:

Hi there!

The equation of position and velocity of an object moving in a straight line with constant acceleration are the following:

x = x0 + v0 · t + 1/2 · a · t²

v = v0 + a · t

Where:

x = position of the truck at time t.

x0 = initial position.

v0 = initial velocity.

a = acceleration.

t = time

v = velocity at time t.

Let's calculate the position of the truck after the first 14.0 s:

x = x0 + v0 · t + 1/2 · a · t²

If we place the origin of the frame of reference at the first stop light, the initial position, x0, is zero. Since the truck starts from rest, v0 = 0. So, the equation of position will be:

x = 1/2 · a · t²

x = 1/2 · 1.60 m/s² · (14.0 s)²

x = 157 m

Then, the truck travels with constant speed (a = 0) for 70.0 s. The equation of position will be:

x = x0 + v · t

In this case, let's consider the initial position as the the position where the car is after 14.0 s (157 m from the stop light). The velocity is the velocity reached after the 14.0 s of acceleration. Let's calculate it with the equation of velocity:

v = v0 + a · t (v0 = 0)

v = 1.60 m/s² · 14.0 s

v = 22.4 m/s

So, the position will be:

x = 157 m + 22.4 m/s · 70.0 s

x = 1725 m

Now, the truck slows down with an acceleration of 3.50 m/s² until it stops (until its velocity is zero). Let's calculate the time at which the velocity of the truck is zero:

v = v0 + a · t

0 = 22.4 m/s - 3.50 m/s² · t

-22.4 m/s / -3.50 m/s² = t

t = 6.4 s

Now let's calculate the position of the truck after that time considering the initial position as the position at which the truck was after the 70.0 s traveling at constant speed (1725 m from the stop light):

x = x0 + v0 · t + 1/2 · a · t²

x = 1725 m + 22.4 m/s · 6.4 s + 1/2 · (-3.50 m/s²) · (6.4 s)²

x = 1797 m

The total distance traveled by the truck is 1797 m

7 0

3 years ago

Rest and motion are relative terms. write in brief​

Rest and motion are relative terms. write in brief