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3 years ago

PLEAASSEEEE HELLLPPPP !!!

Physics

1 answer:

lord [1]3 years ago

6 0

Answer:

a = 3.5 m/s^2

Explanation:

a basic equation of physics is f = ma

we can rearrange that to a= f/m

so plug in your values: a = 175 / 50

you get a = 3.5 m/s^2

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What is the difference in electrical potential energy between two places in an electric field?

Phoenix [80]

Answer: Option (c) is the correct answer.

Explanation:

The difference in electrical potential energy between two places in an electric field is known as potential difference.

Mathematically, potential difference between two given points can be written as follows.

$\Delta V = V_{2} - V_{1}$

where, $\Delta V$ = potential difference

$V_{1}$ = potential at point 1

$V_{1}$ = potential at point 2

4 0

3 years ago

Read 2 more answers

Derive the following equations of motion

xz_007 [3.2K]

Answer:

___________________________________

<h3>a. Let us assume a body has initial velocity 'u' and it is subjected to a uniform acceleration 'a' so that the final velocity 'v' after a time interval 't'. Now, By the definition of acceleration, we have:</h3>

$a = \frac{v - u}{t} \\ or \: at = v - u \\ v = u + at \:$

It is first equation of motion.

___________________________________

<h3>b. Let us assume a body moving with an initial velocity 'u'. Let it's final body 'v' after a time interval 't' and the distance travelled by the body becomes 's' then we already have,</h3>

$v = u + at...........(i) \\ s = \frac{u + v}{2} \times t.........(ii)$

Putting the value of v from the equation (i) in equation (ii), we have,

$s= \frac{u + (u + at)}{2} \times t \: \: \\ or \: s = \frac{(2u + at)t}{2} \\ or \: s = \frac{2ut + a {t}^{2} }{2} \\ s = ut + \frac{1}{2} a {t}^{2}$

It is third equation of motion.

________________________________

<h3>c. Let us assume a body moving with an initial velocity 'u'. Let it's final velocity be 'v' after a time and the distance travelled by the body be 's'. We already have,</h3>

$v = u + at.....(i) \\ s = \frac{u + v}{2} \times t......(ii) \\$

$v = u + at \\ or \: at = v - u \\ t = \frac{v - u}{a}$

Putting the value of t from (i) in the equation (ii)

$s = \frac{u + v}{2} \times \frac{v - u}{a} \\ or \: s = \frac{ {v}^{2} - {u}^{2} }{2a} \\ or \: 2as = {v}^{2} - {u}^{2} \\ {v}^{2} = {u}^{2} + 2as$

It is forth equation of motion.

________________________________

Hope this helps...

Good luck on your assignment..

3 0

3 years ago

Determine the Net Force acting on the object (represented by the solid circle) in this diagram.

wlad13 [49]

Answer:

200 N to the left

Explanation:

If we say left is negative and right is positive, then the net force is:

∑F = -300 N + 100 N

∑F = -200 N

The net force is 200 N to the left.

6 0

3 years ago

Jim pushes hard on a rock that weighs 500 pounds. He pushes with a force of 50 pounds, but the rock doesn't move. How much work

seraphim [82]

Answer:

Zero work

Explanation:

Recall that work done on an object is defined as the product of the net force applied to an object times the distance it travels in the same direction as the force.

Since in this case Jim used a given force to push a rock, but it didn't move, then he did zero work (because the distance moved is zero).

6 0

3 years ago

How do you think that changing the mass of the pendulum bob will affect the period of the pendulum swing?

myrzilka [38]

(Mass does not affect the pendulum's swing. The longer the length of string, the farther the pendulum falls; and therefore, the longer the period, or back and forth swing of the pendulum. The greater the amplitude, or angle, the farther the pendulum falls; and therefore, the longer the period.)

5 0

3 years ago