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2 years ago

If a circuit has a power of 50 W with a current of 4.5 A, what is the resistance in the circuit?

Physics

1 answer:

lawyer [7]2 years ago

8 0

Answer:

${ \rm{power, \: p = current \times p.d}} \\ { \rm{50 = 4.5 \times (current \times resistance)}} \\ { \rm{50 = 4.5 \times (4.5 \times r)}} \\ { \rm{resistance = \frac{50}{ {4.5}^{2} } }} \\ \\ { \rm{resistance = 2.5 \: ohms}}$

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Can someone tell me how to do half life or something because I am so confused and it is due in a couple of hours

Genrish500 [490]

Do you have the equation for half life

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2 years ago

Read 2 more answers

Blood plasma volume for adults is about 3.1 liters. It has a density of 1.020 gml. How many pounds of blood plasma are in your b

kari74 [83]

Answer:

mass is 6.97 pounds

Explanation:

given data

volume = 3.1 liters

density = 1.020 g/ml = 1.02 kg/l

to find out

How many pounds of blood plasma

solution

we know mass formula from density that is

density = mass / volume

mass = density × volume ...............1

so put all value to get mass

mass = 1.02 × 3.1

mass = 3.162 kg

mass = 3.162 × 2.205 pounds

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6 0

3 years ago

A spherical balloon has a radius of 6.55 m and is filled with helium. The density of helium is 0.179 kg/m3, and the density of a

Ksju [112]

Answer:

$M_1 = 317.7 kg$

Explanation:

Mass of the helium gas filled inside the volume of balloon is given as

$m = \rho V$

$m = 0.179(\frac{4}{3}\pi R^3)$

$m = 0.179(\frac{4}{3}\pi 6.55^3)$

$m = 210.7 kg$

now total mass of balloon + helium inside balloon is given as

$M = 210.7 + 990$

$M = 1200.7 kg$

now we know that total weight of balloon + cargo = buoyancy force on the balloon

so we will have

$(M + M_1)g = \rho_{air} V g$

$(1200.7 + M_1) = (\frac{4}{3}\pi 6.55^3) (1.29)$

$1200.7 + M_1 = 1518.4$

$M_1 = 317.7 kg$

3 0

3 years ago

What is the term used for sediments building up at the mouth of the river? (Hint: think New Orleans)

meriva

I believe it’s called Alluvium! It’s where the river mouth is build up of gravel,sand,silt, and clay!!

4 0

3 years ago

The average density of the body of a fish is 1080 kg/m3. To keep from sinking, the fish increases its volumeby inflating an inte

Dimas [21]

Answer:

f = 8 %

Explanation:

given,

density of body of fish = 1080 kg/m³

density of air = 1.2 Kg/m³

density of water = 1000 kg/m²

to protect the fish from sinking volume should increased by the factor f

density of fish + density of water x increase factor = volume changes in water

1080 +f x 1.2 =(1 + f ) x 1000

1080 + f x 1.2 = 1000 + 1000 f

998.8 f = 80

f = 0.0800

f = 8 %

the volume increase factor of fish will be equal to f = 8 %

7 0

3 years ago