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Sergio039 [100]
3 years ago
6

Tartaric acid is present in spinach true or false ​

Physics
1 answer:
sertanlavr [38]3 years ago
7 0

Answer:

<h2>false</h2>

Explanation:

because Oxalic acid is present in spinach

<h2>MARK ME AS BRAINLIST</h2>
You might be interested in
As the people sing in church, the sound level everywhere inside is 101 dB . No sound is transmitted through the massive walls, b
katovenus [111]

The sound level from 1 km away is 46.4 dB and the sound energy radiated through the windows and doors in 20 min is 332.6 J

<h3>What do you mean by sound radiates?</h3>

Multiple plate modes participate in the forced vibration of a baffled plate that produces sound. The emitted sound power depends on the activation of each plate mode by the external pressures as well as the radiation characteristics of the individual plate modes and their mutual interaction via their radiated sound, as shown in eq (20) and (24). The net contribution of the mutual interaction between plate modes to the overall sound power may be disregarded if a plate is activated in a manner that results in a plate vibration field that can be defined as reverberant with an equal distribution of energy over all modes.

(Lw) = 10·log (W/Wo) dB

Given:

sound level,  \beta= 101 dB

Area, A = 22\;m^{2}

Time, \triangle t = 20\;min=1200\;s

Intensity, I=1\times 10^{-12}\;W/m^{2}

r=1\;km=1000\;m

(a)

We know that, Sound level is,

\beta=10\times log(\frac{I}{I_{o} } )

Solving the above equation for sound intensity,

I=I_{o} \times 10^{\frac{\beta}{10} }

I=1 \times 10^{-12}  \times 10^{\frac{101}{10} }

I=0.0126\;W/m^{2}

Therefore, The sound energy is,

E=P\times \triangle t

Substitute P=I \times A in the above equation,

E=I \times A \times \triangle t

E=0.0126 \times 22 \times 1200

E=332.6\;J

(b)

Half of a sphere area with 1 km radius is equal to Area of the sound at 1 km distance,

A_{hemisphere}  = \frac{1}{2} \times 4 r^{2} \pi

Substitute the known value in the above equation ,

A_{hemisphere} = \frac{1}{2} \times 4 (1000)^{2} \pi

A_{hemisphere} = 6283185\;m^{2}

Sound Intensity is,

I = \frac{P}{A_{hemisphere}}

Substitute P=I \times A in the above equation,

I = \frac{I \times A}{A_{hemisphere}}

Substitute the known value in the above equation,

I = \frac{0.0126 \times 22}{6283185}

I = 4.4 \times 10^{-8}\;W/m^{2}

Sound level is,

\beta=10\times log(\frac{I}{I_{o} } )

Substitute the known value in the above equation,

\beta=10\times log(\frac{4.4 \times 10^{-8} }{1 \times 10^{-12} } )

\beta=46.4\;dB

To learn more about sound radiates, Visit:

brainly.com/question/20360072

#SPJ4

8 0
2 years ago
I need help please pleaseeeee
Butoxors [25]
The first one? If not I just guessed
3 0
3 years ago
Hi! Can somebody please help?
dezoksy [38]

Answer:

Diagram A will reach the top first.

Explanation:

If it is going straight, it will go slower. The higher the movement speed the faster it is. Hope this helps!

7 0
3 years ago
Describe the movement of particles at the melting point of a substance with temperature and energy.
Gnesinka [82]

Answer:

As a substance reaches the melting point, the particles begin to move faster, causing the substance to become a liquid.

Explanation:

lmk if you need a different or more detailed answer :)

have a wonderous day <3

7 0
3 years ago
An experiment is set up to test the angular resolution of an optical device when red light (wavelength ????r ) shines on an aper
Neko [114]

Explanation:

As per Rayleigh criterion, the angular resolution is given as follows:

\theta=\frac{1.22 \lambda}{D}

From this expression larger the size of aperture, smaller will be the value of angular resolution and hence, better will be the device i.e. precision for distinguishing two points at very high angular difference is higher.

4 0
4 years ago
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