Question

Calculate the specific heat capacity of titanium if a 43.56 g sample absorbs 476 J as its temperature changes from 20.13 oC to 41.06 oC. (0.522 J/g oC)

Answer 1

The specific heat capacity of Titanium is found as 0.522 J / g°C.

Explanation:

We have to find the specific capacity using the formula as,

q = m × c × ΔT

Where,

q is the heat absorbed by the sample = 476 J

m is the mass of the sample = 43.56 g

c is the specific heat capacity of the sample = ?

ΔT is the temperature difference  = 41.06° C - 20.13°C = 20.93° C

Now, we have to rewrite the equation to get the specific heat capacity as,

c = $\frac{q}{m \times dT}$

 = $\frac{476 }{43.56\times 20.93}$

 = 0.522 J / g°C

So the specific heat capacity of Titanium is found as 0.522 J / g°C.