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kykrilka [37]
3 years ago
14

A sample of oxygen gas was found to effuse at a rate equal to two times that of an unknown gas. what is the molar mass (in g/mol

) of the unknown gas?
Chemistry
1 answer:
inn [45]3 years ago
4 0
<span>128 g/mol Using Graham's law of effusion we have the formula: r1/r2 = sqrt(m2/m1) where r1 = rate of effusion for gas 1 r2 = rate of effusion for gas 2 m1 = molar mass of gas 1 m2 = molar mass of gas 2 Since the atomic weight of oxygen is 15.999, the molar mass for O2 = 2 * 15.999 = 31.998 Now let's subsitute the known values into Graham's equation and solve for m2. r1/r2 = sqrt(m2/m1) 2/1 = sqrt(m2/31.998) 4/1 = m2/31.998 127.992 = m2 So the molar mass of the unknown gas is 127.992 g/mol. Rounding to 3 significant figures gives 128 g/mol</span>
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Answer:

See explaination

Explanation:

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3 years ago
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6 0
3 years ago
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raketka [301]

Answer:

Explanation:

Pair  2.50g of O₂ and 2.50g of  N₂

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Number of moles = \frac{mass }{molarmass}

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4 0
3 years ago
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gogolik [260]

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