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kykrilka [37]
4 years ago
14

A sample of oxygen gas was found to effuse at a rate equal to two times that of an unknown gas. what is the molar mass (in g/mol

) of the unknown gas?
Chemistry
1 answer:
inn [45]4 years ago
4 0
<span>128 g/mol Using Graham's law of effusion we have the formula: r1/r2 = sqrt(m2/m1) where r1 = rate of effusion for gas 1 r2 = rate of effusion for gas 2 m1 = molar mass of gas 1 m2 = molar mass of gas 2 Since the atomic weight of oxygen is 15.999, the molar mass for O2 = 2 * 15.999 = 31.998 Now let's subsitute the known values into Graham's equation and solve for m2. r1/r2 = sqrt(m2/m1) 2/1 = sqrt(m2/31.998) 4/1 = m2/31.998 127.992 = m2 So the molar mass of the unknown gas is 127.992 g/mol. Rounding to 3 significant figures gives 128 g/mol</span>
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A solution is when a solute is added to a water solvent. Since water is neutral, the charge of the said solution is dictated by the charge of the ion. This is the subscript of the element. If it is not stated, then we use the common ion form.

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5 0
4 years ago
1) a solution with a hyrdrogen ion concentration of 1x10^-4 moles/liter would have a PH of what?
lana66690 [7]

Answer:

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1. When con. of H ion is 1*10-4 mol/L

pH = -log(1*10-4) = -(-4) = 4

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7 0
3 years ago
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mamaluj [8]

Answer:

D

Explanation:

We know that the

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now when the sphere is broken down into 8 smaller spheres

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and solving we get

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hence the correct answer is

. The second run has twice the surface area.

8 0
3 years ago
Nickel is extracted from nickel oxide by reduction with carbon.
meriva

Answer:

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