Answer: The mass is 3.58*10^-2 g
Explanation: In order to calculate the mass corresponding to of a small spherical shot of copper inside a graduate cylinder with water we have considered the total volume of water incresed after put the cooper pieces.
In this sense the total increased volume of water is equal to the volume of the 125 small spherical shot of copper so we have the following:
0.5 mL= 125* volume of each piece of cooper=125*Vcopper
Vcooper=0.5/125 mL=5*10^-7 m^3/125=4*10^-9 m^3
Therefore the mass corresponding to each copper piece is equal to:
density of copper* Vcopper piece= 8960 Kg/m^3*4*10^-9 m^3=3.58*10^-5 Kg = 3.58*10^-2 g
Answer:
whirl a rock at the end of a string and it follows a circular path. if the string breaks, the tendency of the rock is to stop
Answer:
Within atoms and molecules electrons can only have certain values for their energy:
We say that energy levels are discretized. We can easily observe the differences between some of these levels by analyzing the light emitted by electrons when moving from one level to another less energetic. The emitted photons have exactly the energy difference between the levels, and as we know that the energy of a photon is:
E = hc / λ
where h is Planck's constant, c is the speed of light and λ is the wavelength.
Explanation:
Each atom is capable of emitting or absorbing electromagnetic radiation, although only at some frequencies that are characteristic of each of the different chemical elements.
If, through the supply of heat energy, a certain element is stimulated in its gas phase, its atoms emit radiation at certain frequencies of the visible, which constitute its emission spectrum.
Thus, the so-called Kirchoff's Law is fulfilled, which indicates that every element absorbs radiation in the same wavelengths in which it emits it. The absorption and emission spectra thus turn out to be the negative one of the other.
Since the spectrum, both emission and absorption, is characteristic of each element, it serves to identify each of the elements of the periodic table, by simple visualization and analysis of the position of the absorption or emission lines in its spectrum.
These characteristics are manifested whether it is a pure element or combined with other elements, so a fairly reliable identification procedure is obtained.
Answer:
Approximately at below the horizon.
- Horizontal component of velocity: .
- Vertical component of velocity: (downwards.)
(Assumption: air resistance on the ball is negligible; .)
Explanation:
Assume that the air resistance on the ball is negligible. The horizontal component of the velocity of the ball would stay the same at until the ball reaches the ground.
On the other hand, the vertical component of the ball would increase (downwards) at a rate of (where is the acceleration due to gravity.) In , the vertical component of the velocity of this ball would have increased by .
However, right after the ball rolled off the edge of the table, the vertical component of the velocity of this ball was . Hence, after the ball rolled off the table, the vertical component of the velocity of this ball would be .
Calculate the magnitude of the velocity of this ball. Let and and denote the horizontal and vertical component of the velocity of this ball, respectively. The magnitude of the velocity of this ball would be .
At after the ball rolled off the table, while . Calculate the magnitude of the velocity of the ball at this moment:
.
Calculate the angle between the horizon and the velocity of the ball (a vector) at that moment. Let denote that angle.
.
For the vector representing the velocity of this ball:
.
Calculate the size of this angle:
.
Notice that the vertical component of the velocity of this ball at that moment points downwards (towards the ground.) Hence, the corresponding velocity should point below the horizon.