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Aleks04 [339]
3 years ago
15

A car is waiting at a red stop light . The light turns green and the car accelerates at a rate of 2.5m/s for 7.5 seconds. How fa

st is the car traveling now
Physics
1 answer:
Mashutka [201]3 years ago
7 0
O miles because it is stopped i think
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4.1 A steel spur pinion has a pitch of 5 teeth/in, 20 full-depth teeth, and a 20° pressure angle. The pinion runs at a speed of
Vesnalui [34]

Answer:

15.07 ksi

Explanation:

Given that:

Pitch (P) = 5 teeth/in

Pressure angle (\Phi) = 20°

Pinion speed (n_p ) = 2000 rev/min

Power (H) = 30 hp

Teeth on gear (N_G) = 50

Teeth on pinion (N_p) = 20

Face width (F) = 1 in

Let us first determine the diameter (d) of the pinion.

Diameter (d) = \frac{N}{P}

=\frac{20}{5}

= 4 in

From the values of Lewis Form Factor Y for (n_p ) = 20 ; at 20°

Y = 0.321

To find the velocity (V); we use the formula:

V = \frac{\pi d n_p}{12}

V = \frac{\pi *4*2000}{12}

V = 2094.40 ft/min

For cut or milled profile; the velocity factor (K_v) can be determined as follows:

K_v = \frac{2000+V}{2000}

K_v = \frac{2000+2094.40}{2000}

= 2.0472

However, there is need to get the value of the tangential load(W^t), in order to achieve that, we have the following expression

W^t=\frac{T}{\frac{d}{2} }

W^t = \frac{63025*H}{\frac{n_pd}{2}}

W^t = \frac{63025*30}{2000*\frac{4}{2}}

W^t = 472.69 lbf

Finally, the bending stress is calculated via the formula:

\sigma = \frac{K_vW^tp}{FY}

\sigma = \frac{2.0472*472.69*5}{1*0.321}

\sigma = 15073.07 psi

\sigma = 15.07 ksi

∴ The estimate of the bending stress = 15.07 ksi

4 0
3 years ago
Read 2 more answers
For an object with a given mass on Earth, calculate the weight of the object with the mass equal in magnitude to the number repr
leonid [27]

<u>Answer:</u> The weight of the object is 29.4 N

<u>Explanation:</u>

To calculate the weight of the object, we use the equation:

W=m\times g

where,

m = mass of the object = 3 kg

g = acceleration due to gravity = 9.8m/s^2

Putting values in above equation, we get:

W=3kg\times 9.8m/s^2\\\\W=29.4N

Hence, the weight of the object is 29.4 N

6 0
3 years ago
a ball is thrown downward with an initial speed of 7 m/s. the ball's velocity after 3 seconds is ____ m/s (g= -9.8m/s^{2}
Karo-lina-s [1.5K]
The speed downwards is 7 + (3*9.8)
7+ 29.4 = 36.4 m/s
5 0
3 years ago
The particle model shows the image of the moving object.
ArbitrLikvidat [17]

Answer:

it does show the objects position

5 0
3 years ago
A piece of iron block moves across a rough horizontal surface before coming to rest. The mass of the block is 1.3 kg, and its in
KengaRu [80]

Answer:

0.0126°C

Explanation:

Kinetic energy sustain by the block,K.E = 1/2× mass×velocity^2

K.E = 1/2 ×1.3×(4^2)

=1/2 × 1.3× 16 = 1.3 ×8 = 10.4J

The internal energy is 71% of kinetic energy is;

U= 71/100 × 10.4 = 7.38J

But U = m × C × ∆T

Where U is internal energy

m is the mass of iron

C is the heat capacity of iron

∆T is the temperature change

By make ∆T the subject of the formula we have

∆T=U/ m×C

=7.38/ 1.3×452= 0.0126°C

6 0
3 years ago
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