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Aleks04 [339]
4 years ago
15

A car is waiting at a red stop light . The light turns green and the car accelerates at a rate of 2.5m/s for 7.5 seconds. How fa

st is the car traveling now
Physics
1 answer:
Mashutka [201]4 years ago
7 0
O miles because it is stopped i think
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Based on its type of chemical bond, which of the following has the highest boiling point?
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Potassium chloride

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Which of the following statements best support the claim that human actions decreased the whooping crane population? (1
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Answer:

D

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A is incorrect because it would actually increase the population...

B is incorrect because other birds do not matter, it is only whooping cranes...

C is incorrect because it would also increase the population.

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3 years ago
Anyone know the answer to this? Please help.. NO LINKS
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There is a ball at rest on a flat floor. What kind of equilibrium is it in? *
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3 0
3 years ago
The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt
lesantik [10]

Answer:

(a) \triangle l=5 mm

(b) 0.033

Explanation:

(a)

Force F=mg where m is mass and g is acceleration due to gravity whose value is taken as 9.81 m/s^{2}

However, for this case, the maximum force is 8 times the weight of runner hence F=8mg

Assume Young's modulus for tendon is 0.15*10^{10} N/m^{2}

Young's modulus is given by

E=\frac {Fl}{A\triangle l} and \triangle l=\frac {Fl}{EA} and substituting F with 8mg we obtain \triangle l=\frac {8mgl}{EA}

Where E is young's modulus, l is stretched length and \triangle l is change in length

Substituting m as 70 kg, g as 9.81 m/s^{2}, l as 15cm=0.15 m, E as 0.15*10^{10} N/m^{2} and A as 110 m^{2}=0.000110 m^{2}

\triangle l=\frac {8*70 Kg*9.81 m/s^{2}*0.15m}{0.15*10^{10} N/m^{2} *0.00011 m^{2}}=0.004994182 m

\triangle l=5 mm

(b)

Strain, \epsilon=\frac {\triangle l}{l} and the fraction of tendon’s length is the ratio of change in length to the stretched length

The fraction of tendon, f is given by

f=\frac {\triangle l}{l}. Substituting \triangle l with 0.005m and l with 0.15m we obtain

\epsilon=f=\frac {0.005}{0.15}=\frac {1}{30}=0.033

Therefore, fraction of the tendon’s length is 0.033

5 0
4 years ago
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