This is possible due to self-discharge. Very small internal currents inevitably occur in these cells over time and they will eventually exhaust the chemistry.
<span>Cobalt-60 is undergoing a radioactivity decay.
The formula of the decay is n=N(1/2)</span>∧(T/t).
<span>Where N </span>⇒ original mass of cobalt
<span> n </span>⇒ remaining mass of cobalt after 3 years
T ⇒ decaying period
t ⇒ half-life of cobalt.
So,
0.675 = 1 × 0.5∧(3/t)
log 0.675 = log 0.5∧(3/t)
3/t = log 0.675 ÷log 0.5
3/t= 0.567
t = 3÷0.567
= 5.290626524
the half-life of Cobalt-60 is 5.29 years.
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Helium and nitrogen because they are both from the noble gas group.
Answer:
Explanation:
Angular velocity ω = 2π / T = 2 x 3 . 14 / (4 x 60 ) = .026 rad / s.
d = D Sin ( ωt + θ ) where D = amplitude = 11 m θ = initial phase.
-11 = 11 sin ( 0 + θ ) = sin θ = -1 , θ = - π /2
So, d = D Sin ( ωt - θ )
d = 11 Sin ( .026 t - π /2 ) is the required equation.
The answer is the last one; the pea plant received different alleles from the parents.
