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gtnhenbr [62]
3 years ago
6

Which of the following is not among the elements to include on your note cards?

Chemistry
1 answer:
Mrac [35]3 years ago
7 0

Answer:

c

Explanation:

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What volume of 7.25 mol/L stock solution in needed to make 3.84 L of 8.50 mol/L solution?
Serjik [45]

Answer:

4.50 L

Explanation:

First we <u>calculate how many moles are there in 3.84 L of a 8.50 mol/L solution</u>:

  • 3.84 L * 8.50 mol/L = 32.64 mol

Now, keeping in mind that

  • Concentration = Mol / Volume

we can calculate the volume of a 7.25 mol/L solution that would contain 32.64 moles:

  • Volume = Mol / Concentration
  • Volume = 32.64 mol ÷ 7.25 mol/L
  • Volume = 4.50 L

So we could take 4.50 L of the 7.25 mol/L solution and evaporate the solvent until only 3.84 L remain.

7 0
3 years ago
What is the next atomic orbital in the series below? 1s, 2s, 2p, 3s, 3p, ___
Angelina_Jolie [31]
D.4s       this would be the answer because after eight electrons are added to the third orbital two have to be added to the fourth before more can be added to the third one. The third orbital can hold 18 electrons, but it first has to have eight, then two on the fourth orbital, then the rest of the ten can be added
7 0
3 years ago
Read 2 more answers
How many mL of 14.5M lithium carbonate solution must be used to deliver 4.20 g of lithium ion
svet-max [94.6K]

Answer:

10.3 g Li) / (6.9410 g Li/mol) x (1 mol Li3PO4 / 3 mol Li) / (0.750 mol/L Li3PO4) = 0.6595 L = 660. mL

Explanation:

7 0
3 years ago
why does a solution of a strong acid conduct electricity better than a solution of a weak acid having the same concentration
Pani-rosa [81]
Strong acids disassociate more compared to weak acids. Since there are more ions, due to more disassociation, there are more ions for electrons to flow through.
3 0
4 years ago
How many moles of ethylene (C2H4) can react with 12.9 liters of oxygen gas at 1.2 atmospheres and 297 Kelvin?
Inga [223]
So in this equation, 3 oxygen will react with 1 ethylene.
then, you convert from 12.9 Liters to moles.
1 mole = 22.4 Liters of gas.
x moles = 12.9 liters

So, 22.4x = 12.9, which means that x = 12.9/22.4, and you get about 0.6, then you divide by 3 because you have 3 Oxygen, and you get about 0.2.

So, 0.2 moles of ethylene C2H4 can react with 12.9 liters of Oxygen Gas.

Hope this Helps :)


3 0
3 years ago
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