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3 years ago

Which are characteristics of scientific questions? Check all that apply.

Chemistry

2 answers:

galina1969 [7]3 years ago

4 0

Answer:

asking about subjective matters

possibly leading to a testable hypothesis

addressing a gap in knowledge

I got soo confused about that last part. I didn't know if that was an option or something you needed to be answered.

Descriptive investigations are not repeatable because they are based only on observations made at a single point in time. The results may vary at a different time. In addition, descriptive investigations do not contain variables that may indicate cause-and-effect relationships.

Leona [35]3 years ago

4 0

Answer:

A C D

Explanation:

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Which atoms are<br> forming a solid?

Marat540 [252]

Answer:

the third one

Explanation:

8 0

3 years ago

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In the experiment "Beer-Lambert’s Law and Spectrophotometry", you prepared a calibration plot similar to the one pictured below.

dexar [7]

Answer:

0.025M

Explanation:

As you must see in your graph, each concentration of the experiment has an absorbance. Following the Beer-Lambert's law that states "The absorbance of a solution is directely proportional to its concentration".

At 0.35 of absorbance, the plot has a concentration of:

8 0

3 years ago

Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced

bazaltina [42]

Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
moles KOH ------------------- 4 moles Mg(OH₂)

moles KOH = 4 x 2 / 1

= 8 moles of KOH

molar mass KOH = 56 g/mol

mass of KOH = n x mm

mass of KOH = 8 x 56

= 448 g of KOH

hope this helps!

3 0

3 years ago

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The formation constant for the reaction ag (aq) 2nh3(aq) ag(nh3)2 (aq) is kf = 1.7 × 107 at 25°c. what is δg° at this temperatur

anzhelika [568]

The value of ΔG° at this temperature is -18034.18 J/mol

Calculation,

Given information

formation constant (Kf)= 1.7 × $10^{7}$

Universal gas constant (R) = 8.314 J/K• mol

Temperature = 25° C = 25 °C + 273 = 300 K

Formula used:

ΔG° = -RT㏑Kf

By putting the valur of R,T, Kf we get the value of ΔG°

ΔG° = - 8.314 J/K• mol×300K㏑ 1.7 × $10^{7}$

ΔG° = -2494.2㏑ 1.7 × $10^{7}$ = -18034.18 J/mol

So, change in standard Gibbs's free energy is -18034.18 J/mol

Learn about formation constant

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8 0

2 years ago

How do you get from mass to moles in this problem?

Zinaida [17]

Answer:

what problem?

8 0

4 years ago