A sample of seawater contains 78.0 grams of NaCl in 2,025 mL of solution. If the molar mass of NaCl is 58.443 g/mol, what is the
molarity of this sample?
0.659 M NaCl
0.823 M NaCl
1.84 M NaCl
2.08 M NaCl
2 answers:
Answer:
that would be 0.659 M NaCl
Answer:
0.659 M NaCl
Explanation:
Equation: Molarity = moles of solute / liters of solution
1. To find moles of solute:
78.0 g NaCl x 1 mol NaCl / 58.44 g NaCl
= 1.334 mol NaCl
2. Calculate molarity
Transfer 2,025 mL to L
1.334 / 2.025 = 0.659 M NaCl (rounded)
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