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WINSTONCH [101]
3 years ago
10

Two identical point charges in outer space are held apart at a distance D. As soon as the charges are released, each begins movi

ng at an acceleration a. If instead they were released at a distance D/2, the acceleration of one charge would be ____.
A. 2a
B. 4a
C. a/2
D. a/4
Physics
2 answers:
AVprozaik [17]3 years ago
6 0

Answer:

B. 4a

Explanation:

Force between the charges is inversely proportional to the square of the distance

=> Force will be 4 times and acceleration will be 4a  

=> Answer b).

yanalaym [24]3 years ago
6 0

Answer: B. 4a

Explanation: The force experienced by the two identical charge is related to thier acceleration a by

F = m*a

m is mass of charge

a is thier acceleration

Also,

Force F is inversely proportional to D². From Coulomb's law

So we have

F ~1/D²

Since the distance D was reduced to D/2

We have that

F¹ ~ 1/(D/2)²

F¹~ 1/D²/4

From the law of reciprocal we have

F¹~ 4*1/D²

Which is the new force due to the decrease in distance to D/2

But 1/D² is original force F.

F¹ ~ 4*F

But F= m*a

F¹ ~ 4*m*a

But m is constant so the only thing changing is the acceleration. So we have, the new acceleration increased by a factor of 4 to be 4*a = 4a.

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Nutka1998 [239]

Answer:

ncandescent solids emit continuous spectra; incandescent gases emit bright-line spectra.

Explanation:

Materials when heated emit a continuous spectrum with all wavelengths.

Hot gas gases emit a spectrum that depends on the transitions between atomic states, therefore it is a discrete spectrum.

When reviewing the answers, the correct one is:

ncandescent solids emit continuous spectra; incandescent gases emit bright-line spectra.

6 0
3 years ago
Please help!!!
Dominik [7]

Answer:

i Believe the correct answer is "An open circuit being changed into a closed circuit"

Explanation:

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3 years ago
Can someone help me a bit on this? Will mark brainliest. ( no physical science option soooo)
Advocard [28]

Answer:

When a light wave goes through a slit, it is diffracted, which means the slit opening acts as a new source of waves. How much a light wave diffracts<em> (how much it fans out)</em> depends on the wavelength of the incident light. The wavelength must be larger than the width of the slit for the maximum diffraction. Thus, for a given slit, red light, because it has a longer wavelength, diffracts more than the blue light.

The corresponding relation for diffraction is

d sin(\theta) \approx \lambda,

where \lambda is the wavelength of light, d is the slit width, and \theta is the diffraction angle.

From this relation we clearly see that the diffraction angle \theta is directly proportional to the wavelength  \lambda of light—longer the wavelength larger the diffraction angle.

7 0
3 years ago
Who reported four “element” classifications, but included some substances that were combinations of elements rather than true el
marishachu [46]

Explanation :

Antoine-Laurent Lavoisier reported four "element" classifications but included some substances that were combinations of elements rather than true elements in his listing.

He is also known as " father of modern chemistry". He gives the modern system of naming chemical substances. He also gives a theory for chemical reactivity of the oxygen.

5 0
3 years ago
A certain first-order reaction is 58% complete in 95 s. What are the values of the rate constant and the half-life for this proc
guajiro [1.7K]

Answer:

0.005734 s^{-1} and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

Explanation:

Expression for rate law for first order kinetics is given by:

a_o=a\times e^{-kt}

where,

k = rate constant  

t = age of sample

a_o = let initial amount of the reactant  

a = amount left after decay process  

We have :

a_o=x

a=58\%\times x=0.58x

t = 95 s

0.58x=x\times e^{-k\times 95 s}

\k= 0.005734 s^{-1}

Half life is given by for first order kinetics::

t_{1/2}=\frac{0.693}{k}

=\frac{0.693}{0.005734 s^{-1}}=120.86 s

0.005734 s^{-1} and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..

3 0
3 years ago
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