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2 years ago

Fill in the blank. You don’t ____ me thass fine _ ___ -Man Tiffany

Physics

2 answers:

Jet001 [13]2 years ago

5 0

Answer:

like, k bye

Hope this helps!

Dahasolnce [82]2 years ago

5 0

Answer:

You dont like me thass fine ok bye

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An elephant lifts 7 large logs from the ground to a container 5 meters above the ground as part of a zoo demonstration. The elep

Alisiya [41]

The work done by the elephant to lift one log is the force multiplied by the height at which the log has been lifted:
$W=Fh=250 N \cdot 5 m=1250 J$
And so, the total work done to lift the 7 logs is 7 times the work done to lift each log:
$W_t = 7 W=7 \cdot 1250 N=8750 J$

5 0

3 years ago

A small 16 kilogram canoe is floating downriver at a speed of 4 m/s. What is the canoe's kinetic energy?

seraphim [82]

Kinetic Energy,K.E=1/2MV²

mass,m=16kg

velocity,v=4m/s

K.E=1/2×16×4²

=128kgm²/s²

=128 Joules

5 0

3 years ago

Read 2 more answers

Describe at least 1 advantage and 1 disadvantaged to learning about a scientific discovery from

Over [174]

Answer:

Explanation:

You can get alot of info from it then again the info could be misleading

Answer:

Explanation:

You can get some good info from the internet but its most likely the wrong info

Answer:

Explanation:

It informs you with the info you need then again you are most likely getting socialy forced information.

8 0

3 years ago

During the first 6 years of its operation, the Hubble Space Telescope circled the Earth 37,000 times, for a total of 1,280,000,0

madreJ [45]

Answer:

$Kilometers\ in\ 1\ Orbit=\frac{1.28*10^9 Km}{3.7*10^4orbits}$

$Kilometers\ in\ 1\ Orbit=3.46*10^4 Km/Orbit$

Explanation:

Given Data:

Numbers of times Telescope cycled around the earth in 6 years=37,000 times

Total Distance traveled in 6 years by the Hubble Space Telescope=1,280,000,000 Km

Find:

Kilometers in one Orbit=?

Solution:

Kilometers in 37,000 Orbits=1,280,000,000 Km

Kilometers in 1 Orbit=1,280,000,000/37,000

In Scientific Notation:

$Kilometers\ in\ 3.7*10^4\ Orbits=1.28*10^9 Km$

$Kilometers\ in\ 1\ Orbit=\frac{1.28*10^9 Km}{3.7*10^4 orbits}$

Kilometers in 1 Orbit=34594.594 Km

Kilometers in 1 Orbit in Scientific notation:

$Kilometers\ in\ 1\ Orbit=3.46*10^4 Km$

8 0

3 years ago

A certain nuclear power plant is capable of producing 1.2×10^9 W of electric power. During operation of the reactor, mass is con

alukav5142 [94]

Answer:

0.00016 kg

Explanation:

Given:

Power = P = 1.2 × 10⁹ Watts

Power = work done / Time

efficiency = 0.30

Input power = 1.2 × 10⁹ / 0.30 = 4 × 10⁹ W

Energy = 4 × 10⁹ x 60 x 60 = 1.44 x 10¹³ joules

E = m c² , where c is the speed of light and m is the mass.

⇒ mass = m = E / c² = (1.44 x 10¹³) / (3 × 10⁸ )²

= 0.00016 kg

6 0

3 years ago