Answer:
For the force due to electromagnetism we use Coulomb’s inverse square law:
F=keq1q2r2
(where F is the electrostatic force, q1 & q2 are the two charges, r is the distance between them, and Coulomb’s Constant ke=14πϵ0=8.99×109Nm2C−2, where ϵ0 is the permittivity of free space)
r=keq1q2F−−−−−√
r=8.99×109Nm2C−2−1.60×10−19C×−1.60×10−19C1.0N−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−√
r=1.52×10−14m
Explanation:
Distance is the total length covered = 2m + 3m = 5m
Displacement is his distance from original position.
Displacement = 2m + (-3)m. Representing the 3m walked back as -3.
Displacement = 2m - 3m = -1m.
So his displacement is 1m behind his original starting point.
Answer:
200 m/s
Explanation:
Given that,
A plane is moving due north, directly towards its destination. Its airspeed is 200 mph. A constant breeze is blowing from west to east at 60 mph.
We need to find the rate at which the plane is moving towards North. It can be given by :
Where
is the angle with the North
Hence, the plane is moving at a rate of 200 m/s.
Answer:
2.73 K
Explanation:
The Cosmic Microwave Background (CMB) radiation are a type of electromagnetic radiations that are released after the explosion of the big bang. It propagates in all direction in space and is moving further with the expansion of the universe. They are not visible but they are helpful in estimating the age of the universe.
These radiations have a wavelength of about 970 μm (approximately 1 mm).
The temperature of the corresponding blackbody of this radiation is approximately <u>2.73 K(-270.42°C)</u> and its extremely cold.
Hello
The period of a wave is the time it takes between two complete oscillations of the wave itself, i.e. it is the time that occurs between two consecutive wavelengths. Therefore, if we want to calculate how many wavelengths pass a certain point in
, we need to divide the total time for the period of the wave, T:
So, the answer is 8 wavelengths.